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# Veritas Prep 10 Year Anniversary Promo Question #1

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Joined: 02 Sep 2009
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Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink]

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17 Sep 2012, 10:00
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80% (02:24) correct 20% (02:01) wrong based on 96 sessions

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Veritas Prep 10 Year Anniversary Promo Question #2

One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course ($1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html To participate, please make sure you provide the correct answer (A,B,C,D,E) and explanation that clearly shows how you arrived at it. Winners will be announced the following day at 10 AM Pacific/1 PM Eastern Time. If A, X, Y, and Z are unique nonzero digits in the equation: XY *YX ____ AYZ And Y > X, the 2-digit number XY = ? A) 13 B) 21 C) 23 D) 24 E) 25 [Reveal] Spoiler: OA _________________  Veritas Prep GMAT Discount Codes Optimus Prep Discount Codes Jamboree Discount Codes Math Expert Joined: 02 Sep 2009 Posts: 38908 Followers: 7739 Kudos [?]: 106258 [1] , given: 11618 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:01 1 This post received KUDOS Expert's post Winner: harshvinayak Official Explanation: Answer is C With abstract calculation problems, start with what you know. Here, you know a few things: -you’re multiplying two 2-digit numbers and in doing so you’ll end up with a 3-digit number -the units digit of the solution is different from the units digit of either number in the problem (which means you cannot use 1) -the two numbers you’re multiplying are in the form that the digits are the same, just flipped This means that A and B are both eliminated (you cannot have a units digit of 1, or the units digit in the answer would be either X or Y). And then try choice D: 42*24 is greater than 1000, so its answer will have more than three digits. The same, then, is true of choice E (52*25 is bigger than 42*24), so choice C is the only plausible answer. _________________ Director Joined: 24 Aug 2009 Posts: 504 Schools: Harvard, Columbia, Stern, Booth, LSB, Followers: 19 Kudos [?]: 735 [0], given: 276 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:08 The answer is C (23) The reasoning is as follows:- B) can't be answer because Y<X D) can't be answer because it XY x YX will give 4 digit number. Thus wrong E) can't be answer because it XY x YX will give 4 digit number. Thus wrong A) can't be answer because it XY x YX will give 3 digit number but the middle digit will not be equal to Y. Thus wrong C) is the correct answer because Y>x & will give 3 digit number & middle digit is Y _________________ If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS. Kudos always maximizes GMATCLUB worth -Game Theory If you have any question regarding my post, kindly pm me or else I won't be able to reply Last edited by fameatop on 17 Sep 2012, 10:13, edited 2 times in total. Founder Joined: 04 Dec 2002 Posts: 14949 Location: United States (WA) GMAT 1: 750 Q49 V42 GPA: 3.5 Followers: 3958 Kudos [?]: 25162 [0], given: 4760 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:09 fameatop wrote: The answer is C (23) The reasoning is as follows:- Please post the full answer/explanation. FYI: to be fair to everyone, we won't be able to take into consideration incomplete posts (answer only without an explanation) and will count complete answers/replies by the the last edit time/date stamp on the post (once you edit it or post again, there will be an update time stamp on it). Thank you for participating and good luck! _________________ Founder of GMAT Club US News Rankings progression - last 10 years in a snapshot - New! Just starting out with GMAT? Start here... Need GMAT Book Recommendations? Best GMAT Books Co-author of the GMAT Club tests Intern Status: :O Joined: 11 Jul 2012 Posts: 43 GMAT 1: 670 Q48 V35 Followers: 1 Kudos [?]: 43 [0], given: 27 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:10 Answer C ! The question could be solved easily using brute force approaching through the options: A) 13 * 31 would give units digit as 3 which cannot be Z B) 21 * 12 would give units digit as 2 which cannot be z C) 23 * 32 would give 736 and satisfies Y> X, hence XY = 23 ! D and E will give answers not in the form of AYZ _________________ http://gmatclub.com/forum/disaster-spelled-in-670-ways-10-not-to-do-s-139230.html GMAT Demystified: http://gmatclub.com/forum/gmat-demystified-great-ebook-to-get-started-with-download-140836.html Tense Tutorial: http://gmatclub.com/forum/uber-awesome-resource-on-tenses-download-140837.html CR Question Bank (LSAT): http://gmatclub.com/forum/critical-reasoning-question-bank-download-140838.html Intern Joined: 09 Jan 2012 Posts: 16 Location: United States Concentration: Strategy, Entrepreneurship GPA: 3.3 WE: Information Technology (Health Care) Followers: 1 Kudos [?]: 6 [0], given: 13 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:12 Answer is C by back solving Eliminate B from the get go then plug in numbers from C (if it wasn't C work through other numbers). 023 032 736 Manager Joined: 12 Sep 2010 Posts: 225 Followers: 2 Kudos [?]: 26 [0], given: 24 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:19 Since Y>X, answer choice B is eliminated. Then I test the answer choices. A) (13)(31)= 403 C) (23)(32)= 736 D) (24)(42)= 1008 E) (25)(52)=1300 Since the answer choice is 3-digit number, D and E are eliminated. That leaves A and C. The question states that the second digit is Y thus C is the correct answer. Intern Joined: 05 Jun 2012 Posts: 22 Followers: 0 Kudos [?]: 0 [0], given: 3 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:26 :OA is C. Y>X--so eliminate B,because 1 is not greater than 2. A,D,E doesn't result in pattern AYZ when XY is multiplied with YX.So,we are left with C. Senior Manager Joined: 19 Apr 2011 Posts: 279 Schools: Booth,NUS,St.Gallon Followers: 5 Kudos [?]: 311 [0], given: 51 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:31 Answer is C . Back solving we find that only 23 satisfies the the conditions . _________________ +1 if you like my explanation .Thanks Intern Joined: 27 May 2012 Posts: 4 Followers: 0 Kudos [?]: 0 [0], given: 0 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:50 I wasn't able to understand the equation initially...looked more like an expression. A. 13*31 = 403 B. Doesn't satisfy Condition Y>X C. 23*32=736 D. 24*42=1008 E. 25*52=1300 D & E are not AYZ format. C is only AYZ format. Hence Ans is 'C' Director Status: Done with formalities.. and back.. Joined: 15 Sep 2012 Posts: 641 Location: India Concentration: Strategy, General Management Schools: Olin - Wash U - Class of 2015 WE: Information Technology (Computer Software) Followers: 49 Kudos [?]: 589 [0], given: 23 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:53 Answer is C. Why do we have to solve problem backward or do lenghty calculations for each number? Just need to read and understand question and possible answers carefully and we can eliminate incorrect choices one by one. The solution to this problem is --- A, X, Y, and Z are unique and are nonzero XY *YX ____ AYZ As per question Y >X and hence ans choice B is eliminated Next in remaining choices X = 1 or X =2. However,if X =1 then unit digit of product (Z) would not be unique hence X <>1 . Hence X =2 And choice A also eliminiated Now we have 3 possible values of Y= 3 ,4 or 5. However if Y=5, unit digit of multiplication would be 0 as X=2. But we know all numbers are non zero. Therefore Ans choice E also eliminated. We are left with C and D. ie 24 or 23. But 24*42 is 4 digit and hence choice D is also eliminated. we are left with one choice that is C. which is the correct answer. _________________ Lets Kudos!!! Black Friday Debrief Senior Manager Joined: 23 Oct 2010 Posts: 384 Location: Azerbaijan Concentration: Finance Schools: HEC '15 (A) GMAT 1: 690 Q47 V38 Followers: 22 Kudos [?]: 354 [0], given: 73 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 10:57 A) 13 13 *31= 403 the last digit of 403 is equal to Y, but we are said that it must be equal to Z,not Y , answ choice A is out B) 21 is out ,since we are told that Y>X C) 23 23*32=736 bingo the second digit of 736 is equal to Y and other digits are in line with the required condition D) 24 24*42=1008 is out, since 1008 is a 4 -digit number, but we need only 3-digit number E) 25 no need to calculate, since we already know that 24*42 is a big number . accordingly, 25*52 is a 4-digit number _________________ Happy are those who dream dreams and are ready to pay the price to make them come true I am still on all gmat forums. msg me if you want to ask me smth Manager Joined: 12 Mar 2012 Posts: 167 Location: India Concentration: Technology, General Management GMAT Date: 07-23-2012 WE: Programming (Telecommunications) Followers: 0 Kudos [?]: 56 [0], given: 4 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 13:03 Quote: If A, X, Y, and Z are unique nonzero digits in the equation: XY *YX ____ AYZ And Y > X, the 2-digit number XY = ? A) 13 B) 21 C) 23 D) 24 E) 25 I got answer as C. A digit is a number from a set of numbers from 0 to 9. B) eliminated at first glance; the condition is given as Y>X but 12 makes it just the opposite ( i.e. X>Y) A) by multiplying 13 and 31 ( i.e. X = 1 and Y = 3), the multiplication does not give Y as 3 in AYZ. Hence, eliminated C) 23*32 gives Y as 3 in AYZ (736); this satisfies all the conditions D) E) Both give result that is greater than 999 i.e. it makes the result of 4 digits. However, A should be a digit and X & Y are single digit numbers as given in the condition that XY is a 2-digit number. Hence both options eliminated This left with C. I wonder if there is a better method to solve such kind of problem. That would be helpful. _________________ FOCUS..this is all I need! Ku-Do! Manager Joined: 14 Feb 2012 Posts: 55 Location: United States WE: Project Management (Consulting) Followers: 1 Kudos [?]: 18 [0], given: 0 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 16:55 Answer is C: 23 because the question says Y>X, so it eliminates answer choice B. start putting the values and looking at the value. value for answer choice A violates the desired format (13*31 = 403) (XY * YX = **Y). values for answer choice D and answer choice E are in 4 digit so out of scope. Answer choice C is the correct answer Intern Joined: 13 Sep 2012 Posts: 5 Followers: 0 Kudos [?]: 0 [0], given: 0 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 19:13 Hi, i also think of the answer as C, but i approached different method to solve: here is my explanation: XY and YX as two digit numbers can be written as following: XY=10X + Y YX=10Y + X and AYZ=100A + 10Y + Z So XY * YX = AYZ can be (10X + Y)*(10Y + X) = 100A + 10Y + Z which is also 100XY + 10(X^2 + Y^2) + XY = 100A + 10Y + Z From: XY *YX AYZ we can know that XY or Z is one digit number otherwise the last digit of X^2 + Y^2 cann't be equal to Y, and considering Y>X we have to check numbers which match the following cases: 1) XY=Z 2) last digit of X^2+Y^2 is Y X Y 1 9 1 8 till 1 2 but none of them matches the second requirement next set is 2 3 2 4 the products of remaining are two digit numbers. let's check the first case 2^2 + 3^2= 13 which is the last digit is 3 ( Y itself) 2^2 + 4^2 = 20 no that is the anwer is 23 which results 23*32=736 thank you for attention Intern Joined: 21 Oct 2011 Posts: 10 Schools: Insead '13 Followers: 0 Kudos [?]: 11 [0], given: 9 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 20:06 Really nice question. I see many have already answered by back solving, which I assume would be the best way to go about it on the test. However, I'm hoping that you are looking for slightly different way to go about it, so here is my attempt: A,X,Y,Z are unique and non-zero 1-9 Xy*yx =ayz since the product is 3 digits, x and y must both be less than 5, and the product of x and y must be less than 10 which gives 1,2,3,4 as the possible values for x and y moving on since the left most digit of the product (a) is not equal to z, it is understood that that this must be because of a carry over from the operation xx+yy. It is also understood that a must be greater than z. -> xx+yy> 10 x*y=z x*x+y*y= 10(x*y - a)+y a>z>y>x, or a>x*y>y>x The only way you will get x*x + y*y, as being greater than 10 while each is less than 5, and the product of x and y is less than 10 is if one is the combos os 2,3 or 2,4. As seen, y is the greater value in either of the combos. However x*x+y*y should have the units digit as y, and only 2,3 -> 2*2+3*3 give the units digit as y (3 in this case). Therefore, the correct answer is 23, answer choice (C). Posted from my mobile device Intern Joined: 21 Oct 2011 Posts: 10 Schools: Insead '13 Followers: 0 Kudos [?]: 11 [0], given: 9 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 17 Sep 2012, 20:14 Really nice question. I see many have already answered by back solving, which I assume would be the best way to go about it on the test. However, I'm hoping that you are looking for slightly different way to go about it, so here is my attempt: A,X,Y,Z are unique and non-zero 1-9 Xy*yx =ayz since the product is 3 digits, x and y must both be less than 5, and the product of x and y must be less than 10 which gives 1,2,3,4 as the possible values for x and y moving on since the left most digit of the product (a) is not equal to z, it is understood that that this must be because of a carry over from the operation xx+yy. It is also understood that a must be greater than z. -> xx+yy> 10 x*y=z x*x+y*y= 10(x*y - a)+y a>z>y>x, or a>x*y>y>x The only way you will get x*x + y*y, as being greater than 10 while each is less than 5, and the product of x and y is less than 10 is if one is the combos os 2,3 or 2,4. As seen, y is the greater value in either of the combos. However x*x+y*y should have the units digit as y, and only 2,3 -> 2*2+3*3 give the units digit as y (3 in this case). Therefore, the correct answer is 23, answer choice (C). Posted from my mobile device Posted from my mobile device Math Expert Joined: 02 Sep 2009 Posts: 38908 Followers: 7739 Kudos [?]: 106258 [1] , given: 11618 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 18 Sep 2012, 08:34 1 This post received KUDOS Expert's post We have a winner! Winner: harshvinayak Official Explanation: Answer is C With abstract calculation problems, start with what you know. Here, you know a few things: -you’re multiplying two 2-digit numbers and in doing so you’ll end up with a 3-digit number -the units digit of the solution is different from the units digit of either number in the problem (which means you cannot use 1) -the two numbers you’re multiplying are in the form that the digits are the same, just flipped This means that A and B are both eliminated (you cannot have a units digit of 1, or the units digit in the answer would be either X or Y). And then try choice D: 42*24 is greater than 1000, so its answer will have more than three digits. The same, then, is true of choice E (52*25 is bigger than 42*24), so choice C is the only plausible answer. _________________ GMAT Club Legend Joined: 09 Sep 2013 Posts: 15472 Followers: 649 Kudos [?]: 209 [0], given: 0 Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] ### Show Tags 11 Sep 2015, 02:46 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Re: Veritas Prep 10 Year Anniversary Promo Question #1 [#permalink] 11 Sep 2015, 02:46 Similar topics Replies Last post Similar Topics: 15 The age of the Earth is approximately 1.3*10^17 seconds, and one year 6 02 Dec 2016, 18:30 58 Leona bought a 1-year,$10,000 certificate of deposit that 13 12 Jun 2016, 09:00
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