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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 03 Dec 2018, 05:57
Hello Karishma ,wana know why is I got this question wrong
If Yury has been writing programming code for 14hrs at a rate of 5 lines of code per 20sec. How many lines of code has he written?
I used the work rate formula =R*T so w=5/20*14hrs =3.5 and it was wrong where lies my reasoning?
Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 03 Dec 2018, 12:27
Hello Karishma is there a tag on GC which I can find your post or solutions only ,to questions,yours seems fast and sweet
Also what is the efficient way to tackle any word problem? Is it
1.Read the question throughout without writing any thing and understand what is being asked before going back to the question to note each statement for creating equations
2.Go straight to what was asked? Noting it and coming back to read the question noting each statement with what was asked in mind
3.Right away note each statement you read and start creating equations before you get to what was asked . Please which is the best or if none is,Kindly suggest because am really struggling with word problems


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 04 Dec 2018, 04:42
VeritasKarishma wrote:
Staphyk wrote:
Hello Karishma is there a tag on GC which I can find your post or solutions only ,to questions,yours seems fast and sweet
Also what is the efficient way to tackle any word problem? Is it
1.Read the question throughout without writing any thing and understand what is being asked before going back to the question to note each statement for creating equations
2.Go straight to what was asked? Noting it and coming back to read the question noting each statement with what was asked in mind
3.Right away note each statement you read and start creating equations before you get to what was asked . Please which is the best or if none is,Kindly suggest because am really struggling with word problems


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Staphyk,

You can put my name in the author field of the Advanced Search feature of GC and search for all my posts in whichever forum you wish to:
https://gmatclub.com/forum/advanced-search/

Different word problems require different approaches. I do favour going one line at a time and evaluating each till I reach the question stem. Here are some recent solutions:
https://gmatclub.com/forum/of-the-stude ... l#p2182147
https://gmatclub.com/forum/in-order-to- ... l#p2182154

Sometimes, you will need to consider the entire question to form equations:
https://gmatclub.com/forum/veritas-prep ... l#p2182196
Thank you


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 04 Dec 2018, 04:48
Please I can I get the verbal forum since here is strictly Quant
Like Veritas STOP strategy

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 04 Dec 2018, 11:00
2 men and 3 women can finish a piece of work in 10 days. while 4 men can do it in 10 days. how many days can 3 men and 3 women take to finish the same work??
Please help me solve this Karishma


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 04 Dec 2018, 22:58
Staphyk wrote:
Please I can I get the verbal forum since here is strictly Quant
Like Veritas STOP strategy

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Sure Staphyk, here is the link to my CR thread. You can put the link of specific CR posts there and I will get to them.
https://gmatclub.com/forum/veritas-prep ... 78026.html

Also, the search link I gave you above works for all forums. Go down in the forums window and you will see the Verbal forums too there.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 04 Dec 2018, 23:06
Staphyk wrote:
2 men and 3 women can finish a piece of work in 10 days. while 4 men can do it in 10 days. how many days can 3 men and 3 women take to finish the same work??
Please help me solve this Karishma


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2 men and 3 women finish it in 10 days
4 men (2 men + 2 men) finish it in 10 days

So 3 women are equivalent to 2 men.

Then 3 men and 3 women are equivalent to 3 men and 2 men i.e. 5 men.

Now, 4 men complete the job in 10 days.
So 5 men will take 10*(4/5) = 8 days (fewer days will be taken so multiply by 4/5, the fraction less than 1)

For more on this method, check this post: https://www.veritasprep.com/blog/2015/1 ... made-easy/
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 00:43
VeritasKarishma wrote:
Staphyk wrote:
2 men and 3 women can finish a piece of work in 10 days. while 4 men can do it in 10 days. how many days can 3 men and 3 women take to finish the same work??
Please help me solve this Karishma


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2 men and 3 women finish it in 10 days
4 men (2 men + 2 men) finish it in 10 days

So 3 women are equivalent to 2 men.

Then 3 men and 3 women are equivalent to 3 men and 2 men i.e. 5 men.

Now, 4 men complete the job in 10 days.
So 5 men will take 10*(4/5) = 8 days (fewer days will be taken so multiply by 4/5, the fraction less than 1)

For more on this method, check this post: https://www.veritasprep.com/blog/2015/1 ... made-easy/
Wow! got it ,Thanks very much


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 12:34
| |Brand X | Brand Y|
MilesperGallon | 40 | 36 |
CostperGallon | $0.80 | $0.75 |
The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on $12 worth of brand Y gasoline?
Hello Karishma am totally confused on this question any efficient method?
Thank you


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 13:22
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 02:32
Staphyk wrote:
| |Brand X | Brand Y|
MilesperGallon | 40 | 36 |
CostperGallon | $0.80 | $0.75 |
The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on $12 worth of brand Y gasoline?
Hello Karishma am totally confused on this question any efficient method?
Thank you


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Here you go: https://gmatclub.com/forum/the-table-ab ... l#p2185231
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 02:37
Staphyk wrote:
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

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You need to find the number of hours required.

When the number of machines go up from 36 to 72, considering everything else constant, will you need more hours or fewer hours? Since the number of machines is more now, you will need less time. More machines will work simultaneously so the work will get completed faster. So you need to multiply 4 by (36/72), the fraction less than 1.

As for orders, from 8 they have gone up to 12 i.e. the work needed to be done has increased. When work to be done increases, keeping everything else constant, will you need more hours or fewer? Since more work has to be done, you need more hours. So you multiply by 12/8, the fraction greater than 1.

4 * (36/72) * (12/8) = 3 hrs

Answer (A)
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 05:41
VeritasKarishma wrote:
Staphyk wrote:
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

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You need to find the number of hours required.

When the number of machines go up from 36 to 72, considering everything else constant, will you need more hours or fewer hours? Since the number of machines is more now, you will need less time. More machines will work simultaneously so the work will get completed faster. So you need to multiply 4 by (36/72), the fraction less than 1.

As for orders, from 8 they have gone up to 12 i.e. the work needed to be done has increased. When work to be done increases, keeping everything else constant, will you need more hours or fewer? Since more work has to be done, you need more hours. So you multiply by 12/8, the fraction greater than 1.

4 * (36/72) * (12/8) = 3 hrs

Answer (A)
got it now ,Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 08 Dec 2018, 10:43
Need your help with this question. Please help

https://gmatclub.com/forum/a-parabola-i ... l#p2186783
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 09 Dec 2018, 04:33
https://gmatclub.com/forum/in-the-xy-co ... 47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 00:00
nitesh50 wrote:
https://gmatclub.com/forum/in-the-xy-coordinate-system-what-is-the-slope-of-the-line-47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh


Nitesh,

Distance of a point from a line is assumed to be the perpendicular distance.
If the line passes through the mid-point of two points, its perpendicular distance from both points will be equal (as explained by walker here: https://gmatclub.com/forum/in-the-xy-co ... ml#p452751)
So one way is that the line passes through origin and through the mid-point of PQ.

Alternatively, the line could be passing through origin and parallel to PQ. Then perpendicular distance from P to the line and perpendicular distance from Q to the line will be equal (perpendicular distance between two parallel lines remains same). In that case the line will have a slope of -2/3.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 00:07
vanam52923 wrote:
Need your help with this question. Please help

https://gmatclub.com/forum/a-parabola-i ... l#p2186783


Here: https://gmatclub.com/forum/a-parabola-i ... l#p2187473
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 01:39
VeritasKarishma wrote:
nitesh50 wrote:
https://gmatclub.com/forum/in-the-xy-coordinate-system-what-is-the-slope-of-the-line-47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh


Nitesh,

Distance of a point from a line is assumed to be the perpendicular distance.
If the line passes through the mid-point of two points, its perpendicular distance from both points will be equal (as explained by walker here: https://gmatclub.com/forum/in-the-xy-co ... ml#p452751)
So one way is that the line passes through origin and through the mid-point of PQ.

Alternatively, the line could be passing through origin and parallel to PQ. Then perpendicular distance from P to the line and perpendicular distance from Q to the line will be equal (perpendicular distance between two parallel lines remains same). In that case the line will have a slope of -2/3.



Hi VeritasKarishma

Thank you for the reply.

So just a clarification:
If 2 points are equidistant from a particular line, then can we say that the perpendicular distance of the points to the line is equal?

Regards
Nitesh
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 01:58
Hello Karishma hope you doing great
Please does being solid on only 500-600 level questions enable me get to Quant 45?
Am now at Quant 30 thus a 15points difference


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 04:03
Again , If 6 typists all working at the same rate can complete a document in 4hrs ,how many hours will it take 4 typist to complete the same document ?

Why is it that when solving this using proportion we use rate in the denominator instead of time like this 6/(1/4)=4/x where x is the rate of 4 typist versus using time in the denominator of the proportions which 6/4 =4/x which gives a wrong ans


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math   [#permalink] 10 Dec 2018, 04:03

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