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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:21
VeritasKarishma wrote:
Staphyk wrote:
Again , If 6 typists all working at the same rate can complete a document in 4hrs ,how many hours will it take 4 typist to complete the same document ?

Why is it that when solving this using proportion we use rate in the denominator instead of time like this 6/(1/4)=4/x where x is the rate of 4 typist versus using time in the denominator of the proportions which 6/4 =4/x which gives a wrong ans


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Look, 6 typists complete it in 4 hrs.
If you have 4 typists, they will take more than 4 hrs (fewer people to do the work).

4 hrs increases by a fraction. What is that fraction? The one by which the number of people have changed.

4 hrs * (6/4) = 6 hrs

Alternatively, if you want to use the work-rate-time formula, try this:

Rate = 6R (because 6 typists work and say rate of each is R)
Time = 4 hrs

Work = Rate*Time = 4*6R = 24R

Now, what happens when we have 4 typists? Rate = 4R
Work is same as before i.e. 24R
Time = ??

Work = Rate*Time

24R = 4R * Time

Time = 6 hrs
well explained,Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:23
VeritasKarishma wrote:
Staphyk wrote:
Hello Karishma hope you doing great
Please does being solid on only 500-600 level questions enable me get to Quant 45?
Am now at Quant 30 thus a 15points difference


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Staphyk, you will need to be comfortable with 650 level questions too to be in that score range. Note that GMAT will word the questions in an innovative way so even though you may know the concepts, it will take a bit of effort to actually arrive at them. You will need to learn to identify the concept being tested in different scenarios. So it is a good idea to work with 600 - 700 level questions.
very well Karishma ,Thanks for the advice


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:50
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 12 Dec 2018, 00:16
Staphyk wrote:
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Hey Staphyk,

Rate of work of A = 1/8
Rate of work of B = 1/16
Rate of work of C = 1/12

Before B and C start working,
A works for 5 hours (2 + 3) and hence does (1/8)*5 = 5/8 of the work.
B works for 3 hrs and hence does (1/16)*3 = 3/16 of the work

So before B and C start working, 5/8 + 3/16 = 13/16 of the work is already over and just 3/16 is left.

Combined rate of B and C = 1/16 + 1/12 = 7/48

Time taken = Work/Rate = (3/16) / (7/48) = 9/7 hrs

I would say 650 level.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 12 Dec 2018, 04:17
VeritasKarishma wrote:
Staphyk wrote:
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Hey Staphyk,

Rate of work of A = 1/8
Rate of work of B = 1/16
Rate of work of C = 1/12

Before B and C start working,
A works for 5 hours (2 + 3) and hence does (1/8)*5 = 5/8 of the work.
B works for 3 hrs and hence does (1/16)*3 = 3/16 of the work

So before B and C start working, 5/8 + 3/16 = 13/16 of the work is already over and just 3/16 is left.

Combined rate of B and C = 1/16 + 1/12 = 7/48

Time taken = Work/Rate = (3/16) / (7/48) = 9/7 hrs

I would say 650 level.
Thanks you , But what makes it 650 is it the calculation involved (eating up time ) ,Wording or logical deductions it demands or some upper level concept one must have


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 13 Dec 2018, 03:02
Staphyk wrote:
VeritasKarishma wrote:
Staphyk wrote:
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Hey Staphyk,

Rate of work of A = 1/8
Rate of work of B = 1/16
Rate of work of C = 1/12

Before B and C start working,
A works for 5 hours (2 + 3) and hence does (1/8)*5 = 5/8 of the work.
B works for 3 hrs and hence does (1/16)*3 = 3/16 of the work

So before B and C start working, 5/8 + 3/16 = 13/16 of the work is already over and just 3/16 is left.

Combined rate of B and C = 1/16 + 1/12 = 7/48

Time taken = Work/Rate = (3/16) / (7/48) = 9/7 hrs

I would say 650 level.
Thanks you , But what makes it 650 is it the calculation involved (eating up time ) ,Wording or logical deductions it demands or some upper level concept one must have


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In an actual GMAT questions, calculations involved are minimal. They will never make it a higher level question. The question is a little convoluted with 3 people working at different rates and for different times and all that needs to be handled separately. That makes this question a little harder.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 13 Dec 2018, 03:24
VeritasKarishma wrote:
Staphyk wrote:
VeritasKarishma wrote:
[quote="Staphyk"]used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Hey Staphyk,

Rate of work of A = 1/8
Rate of work of B = 1/16
Rate of work of C = 1/12

Before B and C start working,
A works for 5 hours (2 + 3) and hence does (1/8)*5 = 5/8 of the work.
B works for 3 hrs and hence does (1/16)*3 = 3/16 of the work

So before B and C start working, 5/8 + 3/16 = 13/16 of the work is already over and just 3/16 is left.

Combined rate of B and C = 1/16 + 1/12 = 7/48

Time taken = Work/Rate = (3/16) / (7/48) = 9/7 hrs

I would say 650 level.
Thanks you , But what makes it 650 is it the calculation involved (eating up time ) ,Wording or logical deductions it demands or some upper level concept one must have


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In an actual GMAT questions, calculations involved are minimal. They will never make it a higher level question. The question is a little convoluted with 3 people working at different rates and for different times and all that needs to be handled separately. That makes this question a little harder.[/quote]Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 17 Dec 2018, 01:54
Hello Karishma ,
Kindly help me with this question ,am confused and don’t know where to start from
In the county of Veenapaniville, there are a total of 50 high schools, of three kinds: 25 public schools, 16 parochial schools, and 9 private independent schools. These 50 schools are divided between three districts: A, B, and C. District A has 18 high schools total. District B has 17 high schools total, and only two of those are private independent schools. If District C has an equal number of each of the three kinds of schools, how many private independent schools are there in District A?


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 17 Dec 2018, 20:36
Staphyk wrote:
Hello Karishma ,
Kindly help me with this question ,am confused and don’t know where to start from
In the county of Veenapaniville, there are a total of 50 high schools, of three kinds: 25 public schools, 16 parochial schools, and 9 private independent schools. These 50 schools are divided between three districts: A, B, and C. District A has 18 high schools total. District B has 17 high schools total, and only two of those are private independent schools. If District C has an equal number of each of the three kinds of schools, how many private independent schools are there in District A?


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LEt's make a 3*3 matrix here:

.................................................. A ......... B ........... C........... Total

Public School...........................................................................25

Parochial School......................................................................16

Private Independent School......................2...............................9

Total.........................................18..........17.............................50


Step 2: C has equal number of the 3 school types

.................................................. A ......... B .............. C......................... Total

Public School..............................................................5...........................25

Parochial School.........................................................5...........................16

Private Independent School......................2.................5...........................9

Total.........................................18..........17.......50-18-17=15.................50


Step 3: No of private independent schools in district A

.................................................. A ......... B .............. C......................... Total

Public School..............................................................5...........................25

Parochial School.........................................................5...........................16

Private Independent School.......9-2-5.......2.................5...........................9

Total.........................................18..........17...............15.................50


Answer: A has 2 private independent schools



Alternatively,

All you need to do is focus on what you need. You need to find the number of private schools in A. Total no. of private schools is 9 and in B, you have 2 of them. So there are 7 private schools distributed between A and C. All you need to find is the number of private schools in C to get the number of private schools in A. What is given to you about C? C has an equal number of each of the three kinds of schools. Total number of schools in C = 50 - (18 + 17) = 15. So no. of private schools in C = 15/3 = 5
Therefore, A must have 7 - 5 = 2 private schools.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 18 Dec 2018, 08:13
VeritasKarishma wrote:
Staphyk wrote:
Hello Karishma ,
Kindly help me with this question ,am confused and don’t know where to start from
In the county of Veenapaniville, there are a total of 50 high schools, of three kinds: 25 public schools, 16 parochial schools, and 9 private independent schools. These 50 schools are divided between three districts: A, B, and C. District A has 18 high schools total. District B has 17 high schools total, and only two of those are private independent schools. If District C has an equal number of each of the three kinds of schools, how many private independent schools are there in District A?


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LEt's make a 3*3 matrix here:

.................................................. A ......... B ........... C........... Total

Public School...........................................................................25

Parochial School......................................................................16

Private Independent School......................2...............................9

Total.........................................18..........17.............................50


Step 2: C has equal number of the 3 school types

.................................................. A ......... B .............. C......................... Total

Public School..............................................................5...........................25

Parochial School.........................................................5...........................16

Private Independent School......................2.................5...........................9

Total.........................................18..........17.......50-18-17=15.................50


Step 3: No of private independent schools in district A

.................................................. A ......... B .............. C......................... Total

Public School..............................................................5...........................25

Parochial School.........................................................5...........................16

Private Independent School.......9-2-5.......2.................5...........................9

Total.........................................18..........17...............15.................50


Answer: A has 2 private independent schools



Alternatively,

All you need to do is focus on what you need. You need to find the number of private schools in A. Total no. of private schools is 9 and in B, you have 2 of them. So there are 7 private schools distributed between A and C. All you need to find is the number of private schools in C to get the number of private schools in A. What is given to you about C? C has an equal number of each of the three kinds of schools. Total number of schools in C = 50 - (18 + 17) = 15. So no. of private schools in C = 15/3 = 5
Therefore, A must have 7 - 5 = 2 private schools.
Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 19 Dec 2018, 19:54
HI VeritasKarishma

Is there any non algebraic way of doing the following question?
We could do it by number plugging but I was looking for something logical and fast.
Do let me know!

https://gmatclub.com/forum/bill-and-ted ... s#p2193868

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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 20 Dec 2018, 05:00
nitesh50 wrote:
HI VeritasKarishma

Is there any non algebraic way of doing the following question?
We could do it by number plugging but I was looking for something logical and fast.
Do let me know!

https://gmatclub.com/forum/bill-and-ted ... s#p2193868

Regards
Nitesh


Nitesh, I have come across such questions often and used the options to arrive at the answer. Since the relation is quadratic, I haven't been able to find a straight forward logical way to arrive at the answer.
https://gmatclub.com/forum/bill-and-ted ... l#p2194227
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 20 Dec 2018, 10:03
https://gmatclub.com/forum/if-m-and-n-a ... 01636.html


Hi VeritasKarishma

in this question the final condition becomes:

IS (1/3+n/3) > Rem (1/3+m/3)?

Now the mistake I made on this question is that
I cancelled remainder of 1 on each side.

SO my statement then became:
n/3 > m/3

In this case when analysing option B, I found the option to be NS.

n/3=2
then m/3=
0 yes
1 yes
2 no

Now why can't we cancel the remainders on either side.
Can you tell me why can't I do cancel the remainders on either side.
Any additional theory on this specific concept will really help me.
Looking forward to your analysis.

Regards
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 21 Dec 2018, 01:37
nitesh50 wrote:
https://gmatclub.com/forum/if-m-and-n-are-positive-integers-is-the-remainder-of-101636.html


Hi VeritasKarishma

in this question the final condition becomes:

IS (1/3+n/3) > Rem (1/3+m/3)?

Now the mistake I made on this question is that
I cancelled remainder of 1 on each side.

SO my statement then became:
n/3 > m/3

In this case when analysing option B, I found the option to be NS.

n/3=2
then m/3=
0 yes
1 yes
2 no

Now why can't we cancel the remainders on either side.
Can you tell me why can't I do cancel the remainders on either side.
Any additional theory on this specific concept will really help me.
Looking forward to your analysis.

Regards
nitesh


Is remainder of (n + 1)/3 greater than the remainder of (m + 1)/3?
Is this same as saying "Is remainder of n/3 greater than remainder of m/3?"
- No, it is not.

Say, n = 5, m = 4

n/3 remainder = 2 (Greater)
m/3 remainder = 1

(n + 1)/3 remainder = 0
(m + 1)/3 remainder = 2 (Greater)

So the two questions are not equivalent. Adding 1 to number doesn't necessarily add 1 to the remainder. It could make the remainder go 0.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 21 Dec 2018, 22:09
Dear Karishma ,
Please what does it mean if I can’t solve a question like the below ?
A room contains 160 people,15% of whom a women.A group of people,30% of whom are women leaves the room. Of the people remaining the room,10% are women ,How many people left the room?

Regards,
Staphyk


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 24 Dec 2018, 03:07
Staphyk wrote:
Dear Karishma ,
Please what does it mean if I can’t solve a question like the below ?
A room contains 160 people,15% of whom a women.A group of people,30% of whom are women leaves the room. Of the people remaining the room,10% are women ,How many people left the room?

Regards,
Staphyk


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Hey Staphyk,

You cannot judge yourself based on a single question. The best of us sometimes make the silliest of mistakes or experience brain freeze on a question. That said, it seems many people get stuck in this question so though it may seem easy after looking at the solution, it certainly may not seem that way the first time you see it.

Tip: Think of weighted average whenever you mix two groups together or whenever you separate a group into two different groups.
In this question, a group fo 160 people split into two groups - one group that leaves (L) and one group that is remaining (R).

wL/wR = (10 - 15)/(15 - 30) = 1/3

So 1/4th of the total people left i.e. (1/4)*160 = 40 people left.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 24 Dec 2018, 04:32
VeritasKarishma wrote:
Staphyk wrote:
Dear Karishma ,
Please what does it mean if I can’t solve a question like the below ?
A room contains 160 people,15% of whom a women.A group of people,30% of whom are women leaves the room. Of the people remaining the room,10% are women ,How many people left the room?

Regards,
Staphyk


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Hey Staphyk,

You cannot judge yourself based on a single question. The best of us sometimes make the silliest of mistakes or experience brain freeze on a question. That said, it seems many people get stuck in this question so though it may seem easy after looking at the solution, it certainly may not seem that way the first time you see it.

Tip: Think of weighted average whenever you mix two groups together or whenever you separate a group into two different groups.
In this question, a group fo 160 people split into two groups - one group that leaves (L) and one group that is remaining (R).

wL/wR = (10 - 15)/(15 - 30) = 1/3

So 1/4th of the total people left i.e. (1/4)*160 = 40 people left.
Simple solution,Thanks Karishma


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 12 Jan 2019, 03:09
HI VeritasKarishma


Please have a look at this question.

https://gmatclub.com/forum/is-a-positiv ... l#p2206226


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 14 Jan 2019, 02:16
Hi,

I am facing this silly doubt which is bothering me in DS questions.

Is \(\sqrt{n}\) = n
or +n or -n?

To think of it \(\sqrt{81}\) , we can square 9 and -9 to get it.
But after reading many sources and watching youtube videos, they say it can only be positive.

Secondly, if it is only positive then following is contradictory

\(\sqrt{X^2}\) = |X|
Then X can take both positive and negative values, so this is contradictory.


I was solving a question and I struggled with this equation
\(p^2\)= \((q+1)^2\)
What would this give?

Thanks.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 14 Jan 2019, 02:28
Hello Karishma,

I have a very general question on how to simplify arithmetic computations.
I have to compute 0.17*(26.4/1.65). To simplify it I did rewrite it as: 17*264/1650

Now the solution I found to simplify this calculation further more is the following: (17)*(3*8*11)/(3*5*11*10)

Do you have any tips on how to quickly find these factors of the products I want to simplify? I tried it using prime factorization but it takes too long....

Thanks

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math   [#permalink] 14 Jan 2019, 02:28

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