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 Author: Bunuel [ 26 Apr 2019, 05:41 ] Post subject: Which of the following gives all possible values of x in the figure ab Which of the following gives all possible values of x in the figure above?A. 1 < x < 4B. 1 < x < 7C. 3 < x < 5D. 4 < x < 7E. 5 < x < 12PS05602.01Quantitative Review 2020 NEW QUESTIONAttachment: 2019-04-26_1739.png [ 8.42 KiB | Viewed 15283 times ]

 Author: BrentGMATPrepNow [ 26 Apr 2019, 09:07 ] Post subject: Which of the following gives all possible values of x in the figure ab Bunuel wrote: Which of the following gives all possible values of x in the figure above?A. 1 < x < 4B. 1 < x < 7C. 3 < x < 5D. 4 < x < 7E. 5 < x < 12IMPORTANT RULE: If two sides of a triangle have lengths A and B, then . . . DIFFERENCE between A and B < length of third side < SUM of A and BApplying the above rule, we get: 4 - 3 < x < 4 + 3Simplify: 1 < x < 7Answer: BRELATED VIDEO

 Author: m1033512 [ 26 Apr 2019, 19:04 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab Sum of the two sides should always be greater than the third side only B satisfy this condition award kudos if helpful

 Author: Archit3110 [ 28 Apr 2019, 02:50 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab third side rule simplesum <7 and >1 IMO B Bunuel wrote: Which of the following gives all possible values of x in the figure above?A. 1 < x < 4B. 1 < x < 7C. 3 < x < 5D. 4 < x < 7E. 5 < x < 12PS05602.01Quantitative Review 2020 NEW QUESTIONAttachment:2019-04-26_1739.png

 Author: EgmatQuantExpert [ 23 May 2019, 04:20 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab SolutionGivenIn this question, we are given• The diagram of a triangle PQR, with side lengths PQ = 3, QR = 4, and PR = xTo FindWe need to determine• Among the given choices, which range defines all possible values of x.Approach & WorkingWe know that, for any given triangle, sum of any two sides is always greater than the third side.Therefore, we can say• 3 + 4 > xOr, x < 7Similarly, x + 4 > 3 Or, x > 1Combining the two results, we can conclude 1 < x < 7.Hence, the correct answer is option B. Author: ScottTargetTestPrep [ 27 May 2019, 18:17 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab Bunuel wrote: Which of the following gives all possible values of x in the figure above?A. 1 < x < 4B. 1 < x < 7C. 3 < x < 5D. 4 < x < 7E. 5 < x < 12PS05602.01Quantitative Review 2020 NEW QUESTIONAttachment:2019-04-26_1739.pngIn any triangle, the length of the third side must be more than the difference of the other sides and less than the sum of those two sides. Therefore, we have:4 - 3 < x < 4 + 31 < x < 7Answer: B

 Author: MHIKER [ 19 Nov 2020, 08:50 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab Bunuel wrote: Which of the following gives all possible values of x in the figure above?A. 1 < x < 4B. 1 < x < 7C. 3 < x < 5D. 4 < x < 7E. 5 < x < 12PS05602.01Quantitative Review 2020 NEW QUESTIONAttachment:2019-04-26_1739.pngA property of a triangle is: The length of the third side must be greater than the difference of the other two sides and less than the sum of those two sides. So, $$4 - 3 < x < 4 + 3$$ $$= 1 < x < 7$$The Answer is B

 Author: bumpbot [ 20 Sep 2022, 07:26 ] Post subject: Re: Which of the following gives all possible values of x in the figure ab Hello from the GMAT Club BumpBot!Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

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