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Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.
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Author:  MathRevolution [ 27 Jun 2019, 02:35 ]
Post subject:  Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

[GMAT math practice question]

Both roots of the quadratic equation \(x^2-39x+a = 0\) are prime numbers. How many different possible values of a are there?

\(A. 1\)

\(B. 2\)

\(C. 3\)

\(D. 4\)

\(E. 5\)

Author:  nick1816 [ 27 Jun 2019, 02:52 ]
Post subject:  Re: Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

IMO Answer must be A.

Sum of roots = 39
Sum is odd that implies one root is even and other is odd.

There is only 1 even prime number that is 2, hence other root must be 39-2=37.

a= 2*37=74

There is only one value possible.


MathRevolution wrote:
[GMAT math practice question]

Both roots of the quadratic equation \(x^2-39x+a = 0\) are prime numbers. How many different possible values of a are there?

\(A. 1\)

\(B. 2\)

\(C. 3\)

\(D. 4\)

\(E. 5\)

Author:  MidhilaMohan [ 27 Jun 2019, 03:15 ]
Post subject:  Re: Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

nick1816 wrote:
IMO Answer must be A.

Sum of roots = 39
Sum is odd that implies one root is even and other is odd.

There is only 1 even prime number that is 2, hence other root must be 39-2=37.

a= 2*37=74

There is only one value possible.


MathRevolution wrote:
[GMAT math practice question]

Both roots of the quadratic equation \(x^2-39x+a = 0\) are prime numbers. How many different possible values of a are there?



\(A. 1\)

\(B. 2\)

\(C. 3\)

\(D. 4\)

\(E. 5\)



I agree with your answer. Even I have arrived at the same but here the answer is showing as 4. is the answer marked correctly?

Author:  nick1816 [ 27 Jun 2019, 03:22 ]
Post subject:  Re: Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

He should change the question to "What's the unit digit of a". LOL
This guy gonna post official solution in next 2 days. Gotta wait till then!!
Midhila wrote:
nick1816 wrote:
IMO Answer must be A.

Sum of roots = 39
Sum is odd that implies one root is even and other is odd.

There is only 1 even prime number that is 2, hence other root must be 39-2=37.

a= 2*37=74

There is only one value possible.


MathRevolution wrote:
[GMAT math practice question]

Both roots of the quadratic equation \(x^2-39x+a = 0\) are prime numbers. How many different possible values of a are there?



\(A. 1\)

\(B. 2\)

\(C. 3\)

\(D. 4\)

\(E. 5\)



I agree with your answer. Even I have arrived at the same but here the answer is showing as 4. is the answer marked correctly?

Author:  MathRevolution [ 30 Jun 2019, 18:05 ]
Post subject:  Re: Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

=>

Assume \(p\) and \(q\) are roots of \(x^2-39x+a = 0.\)

Then \((x-p)(x-q) = x^2 –(p+q)x + pq = x^2-39x+a = 0\)

So, \(p + q = 39\) and \(pq = a.\)

Since \(p\) and \(q\) are prime numbers and \(p + q = 39\) is an odd number, one of \(p\) and \(q\) is an even prime number. Since the only even prime number is \(2\), one of \(p\) and \(q\) must be \(2\).

Let \(p = 2\). Then \(q = 37\),

and \(a = 2*37 = 74.\)

There is only one possible value of \(a\).

Therefore, the answer is A.
Answer: A

Author:  bumpbot [ 22 Nov 2022, 10:57 ]
Post subject:  Re: Both roots of the quadratic equation x^2-39x+a = 0 are prime numbers.

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