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 Author: Bunuel [ 27 Jun 2022, 19:15 ] Post subject: If x is a positive integer, and m = 1^(x+1), then what is the value of If x is a positive integer, and $$m=3^{x+1}$$, then what is the value of $$9^{2x}$$ in terms of m?(A) $$\frac{m^2}{9}$$(B) $$\frac{m^2}{81}$$(C) $$\frac{m^3}{9}$$(D) $$\frac{m^4}{3}$$(E) $$\frac{m^4}{81}$$

 Author: Iotaa [ 27 Jun 2022, 20:50 ] Post subject: Re: If x is a positive integer, and m = 1^(x+1), then what is the value of Bunuel wrote:If x is a positive integer, and $$m=3^{x+1}$$, then what is the value of $$9^{2x}$$ in terms of m?(A) $$\frac{m^2}{9}$$(B) $$\frac{m^2}{81}$$(C) $$\frac{m^3}{9}$$(D) $$\frac{m^4}{3}$$(E) $$\frac{m^4}{81}$$$$m=3^{x+1}$$; $$Also, m=3^{x} *3$$$$9^{2x} = 3^{4x} = 3^{x} X 3^{x} X 3^{x} X 3^{x}$$ $$Also, 3^{x}$$ = m/3 => $$3^{x} X 3^{x} X 3^{x} X 3^{x}$$ = m/3 X m/3 X m/3 X m/3 = $$m^{4}/81$$ , option E

 Author: Kinshook [ 27 Jun 2022, 21:24 ] Post subject: Re: If x is a positive integer, and m = 1^(x+1), then what is the value of Asked: If x is a positive integer, and $$m=3^{x+1}$$, then what is the value of $$9^{2x}$$ in terms of m?$$9ˆ{2x+2} = 81*9ˆ{2x} = 3ˆ{4x + 4} = mˆ4$$$$9ˆ{2x} = \frac{mˆ4}{81}$$IMO E

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