In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE?
(1) The circle has a radius of length 3.
(2) CDE is isosceles.
Attachment:
2015-12-13_1646.png [ 19.45 KiB | Viewed 6832 times ]
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| Author: | Bunuel [ 13 Dec 2015, 05:48 ] |
| Post subject: | In the figure above, a circle is inscribed in square ABCD. What is the |
In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE? (1) The circle has a radius of length 3. (2) CDE is isosceles. Attachment: 2015-12-13_1646.png [ 19.45 KiB | Viewed 6832 times ] |
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| Author: | rsh12 [ 13 Dec 2015, 19:47 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
I think the answer is A. Its a Square and the radius is given - we can get Base and height. Thus area of triangle! |
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| Author: | rohit8865 [ 31 Jul 2016, 04:21 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
Bunuel wrote: In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE? (1) The circle has a radius of length 3. (2) CDE is isosceles. Attachment: 2015-12-13_1646.png although i get ans A i have some doubts regarding option B (2) CDE is isosceles. can we say then ED=EC and in that case both EC and ED will meet at point E which is mid of AB? Experts plz reply... regards |
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| Author: | hsbinfy [ 31 Jul 2016, 04:58 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
rohit8865 wrote: Bunuel wrote: In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE? (1) The circle has a radius of length 3. (2) CDE is isosceles. Attachment: 2015-12-13_1646.png although i get ans A i have some doubts regarding option B (2) CDE is isosceles. can we say then ED=EC and in that case both EC and ED will meet at point E which is mid of AB? Experts plz reply... regards for statemtn 2 u r right..but u didn't look at more possibilities its GIVEN CDE is isosceles , BUT the sides which are equal its not given(that u assumed ED=EC) any 2 sides can be equal. thats y its insufficient hope it helps |
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| Author: | rohit8865 [ 31 Jul 2016, 05:18 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
hsbinfy wrote: rohit8865 wrote: Bunuel wrote: In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE? (1) The circle has a radius of length 3. (2) CDE is isosceles. Attachment: 2015-12-13_1646.png although i get ans A i have some doubts regarding option B (2) CDE is isosceles. can we say then ED=EC and in that case both EC and ED will meet at point E which is mid of AB? Experts plz reply... regards for statemtn 2 u r right..but u didn't look at more possibilities its GIVEN CDE is isosceles , BUT the sides which are equal its not given(that u assumed ED=EC) any 2 sides can be equal. thats y its insufficient hope it helps yes any two sides can be equal but as it is square then in sideways triangles EC and ED are hypotenuse which is greater than side CD thus i m concluding only ED =EC  thanks |
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| Author: | JenniferAtKaplan [ 04 Aug 2016, 13:34 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
Hi rohit8865, You are correct that statement 2 tells us that EC=ED because they are each a hypotenuse of a triangle that shares a side with the square, and therefore they must both be larger than the side length CD. That would also mean that point E is the midpoint of side AB. The real reason that statement 2 is insufficient is that it doesn't provide any of the side lengths. Without any measurements, we cannot calculate the area of the triangle. Best, Jennifer Kindy |
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| Author: | rajendra00 [ 22 Nov 2016, 22:40 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
hi bunuel, Can you pls explain this question ?? |
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| Author: | Bunuel [ 23 Nov 2016, 02:46 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
rajendra00 wrote: hi bunuel, Can you pls explain this question ?? In the figure above, a circle is inscribed in square ABCD. What is the area of ∆ CDE? Notice that the are of ∆ CDE is 1/2*(altitude)*(base) = 1/2*BC*CD. Since ABCD is a square then the area of ∆ CDE is 1/2*(side)^2. (1) The circle has a radius of length 3 --> diameter = side of the square = 6 --> the area of ∆ CDE is 1/2*(side)^2 = 18. Sufficient. (2) CDE is isosceles. No actual measurements are given. Not sufficient. Answer: A. |
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| Author: | bumpbot [ 25 Dec 2022, 13:14 ] |
| Post subject: | Re: In the figure above, a circle is inscribed in square ABCD. What is the |
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