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 Author: nalinnair [ 22 May 2016, 23:00 ] Post subject: For all x, the expression x* is defined to be ax + a, where a is...... For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$

 Author: OptimusPrepJanielle [ 23 May 2016, 00:02 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$x* = ax + a = a (x + 1)2* = ?Statement 1: 3* = 2or 3a + a = 2a = 1/2Hence 2* = (1/2)*(2 + 1) = 3/2SUFFICIENTStatement 2: 5* = 3Or 5a + a = 3a = 1/2Hence 2* = (1/2)*(2 + 1) = 3/2SUFFICIENTCorrect Option: D

 Author: arirux92 [ 24 May 2016, 04:54 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... Trying to solve these equations is unnecessary and in 90% of DS questions a waste of timeA) 3a + a = 2 Linear eqn with 1 variable, 1 solution. sufficient2) 5 a + a = 6Same reasoning as aboveAnswer : D

 Author: dineshril [ 19 Dec 2017, 07:47 ] Post subject: For all x, the expression x* is defined to be ax + a, where a is...... nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$Given=>x*=ax+a=>x*=a(x+1)Therefore=>2*=a(2+1)=>2*=3a ----(1)so if we can find the value of 'a' we can hav the value of 2*NowStatement 1 says 3*=23*=4a from (1)=> 4a=2=> a=2/4=1/2sufficientStatement 2 says 5*=35*=6a from (1)=> 6a=3=> a=3/6=1/2sufficientTherefore option 'D'Thanks

 Author: amanvermagmat [ 19 Dec 2017, 08:50 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... dineshril wrote:nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$Given=>x*=ax+a=>x*=a(x+1)Therefore=>2*=a(2+1)=>2*=3a ----(1)so if we can find the value of 'a' we can hav the value of 2*NowStatement 1 says 3*=23*=4a from (1)=> 4a=2=> a=2/4=1/2sufficientStatement 2 says 5*=35*=6a from (1)=> 6a=3=> a=3/6=1/2sufficientTherefore option 'E'ThanksHi Correct solution. But when each statement alone is sufficient to answer a question, the answer is D I guess that was a typo

 Author: dineshril [ 19 Dec 2017, 11:30 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... amanvermagmat wrote:dineshril wrote:nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$Given=>x*=ax+a=>x*=a(x+1)Therefore=>2*=a(2+1)=>2*=3a ----(1)so if we can find the value of 'a' we can hav the value of 2*NowStatement 1 says 3*=23*=4a from (1)=> 4a=2=> a=2/4=1/2sufficientStatement 2 says 5*=35*=6a from (1)=> 6a=3=> a=3/6=1/2sufficientTherefore option 'E'ThanksHi Correct solution. But when each statement alone is sufficient to answer a question, the answer is D I guess that was a typo Hi AmanThanks for the correction. Its 'D'

 Author: KanishkM [ 29 Jan 2019, 23:17 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$So basically 2^* will be 2a + a => 3aNow if i can get value of a, i will be good (1) $$3^* = 2$$3a + a = 2 a = 1/2We are good (2) $$5^* = 3$$6a = 3a = 1/2We are good Both statements are SufficientDPosted from my mobile device

 Author: MHIKER [ 16 Dec 2020, 07:22 ] Post subject: For all x, the expression x* is defined to be ax + a, where a is...... nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$$$2^*=a2+a=2a+a;$$ We need know the value of $$a$$(1)$$3^*=a3=+a=3a+a; \ given \ that \ 3a+a=2; 4a=2; a=\frac{1}{2} \ Sufficient$$(2) $$5^*=53=+a=5a+a; \ given \ that \ 5a+a=3; 6a=3; a=\frac{1}{2} \ Sufficient$$The answer is $$D$$

 Author: ScottTargetTestPrep [ 16 Jun 2021, 04:25 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... nalinnair wrote:For all $$x$$, the expression $$x^*$$ is defined to be $$ax + a$$, where $$a$$ is a constant. What is the value of $$2^*$$?(1) $$3^* = 2$$(2) $$5^* = 3$$Solution:Question Stem Analysis:We need to determine the value of 2* given that x* = ax + a. Therefore, we need to determine the value of a(2) + a = 3a. We see that if we can determine the value of a, then we can determine the value of 2*.Statement One Alone:We see that a(3) + a = 2. So we have 4a = 2 or a = ½. Since 2* = 3a, then 2* = 3(½) = 3/2. Statement one alone is sufficient. Statement Two Alone:We see that a(5) + a = 3. So we have 6a = 3 or a = ½. Since 2* = 3a, 2* = 3(½) = 3/2. Statement two alone is sufficient. Answer: D

 Author: bumpbot [ 29 Nov 2022, 08:14 ] Post subject: Re: For all x, the expression x* is defined to be ax + a, where a is...... Hello from the GMAT Club BumpBot!Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

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