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 Author: Bunuel [ 05 Jul 2018, 23:15 ] Post subject: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 What is the value of (x - 1)(y + 1) ?(1) x + y = 4(2) xy = 3M36-130

 Author: Bunuel [ 16 Nov 2021, 08:26 ] Post subject: Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 Bunuel wrote:What is the value of (x - 1)(y + 1) ?(1) x + y = 4(2) xy = 3M36-130Official Solution:What is the value of $$(x - 1)(y + 1)$$ ? (1) $$x + y = 4$$ The above equation has infinitely many solutions for $$x$$ and $$y$$. Not sufficient. (2) $$xy = 3$$ The above equation has infinitely many solutions for $$x$$ and $$y$$. Not sufficient. (1)+(2) From $$x + y = 4$$ we can get that $$x=1$$ and $$y=3$$ or $$x=3$$ and $$y=1$$. For the first case, $$(x - 1)(y + 1)=0$$ but for the second case, $$(x - 1)(y + 1)=6$$. Not sufficient. Answer: E

 Author: PKN [ 05 Jul 2018, 23:36 ] Post subject: Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 Bunuel wrote:What is the value of (x - 1)(y + 1) ?(1) x + y = 4(2) xy = 3Individually insufficient.combining, we have two values of both x and y for which (x - 1)(y + 1) will have two values.hence, insufficient.Ans (E)

 Author: mygmat0101 [ 06 Jul 2018, 11:00 ] Post subject: Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 Eindividual statements are insufficient.we'll get two values of x and y x =1,3 y=3,1so the binomial has 2 valuesso E

 Author: Bunuel [ 24 Dec 2018, 00:38 ] Post subject: Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 Bunuel wrote:What is the value of (x - 1)(y + 1) ?(1) x + y = 4(2) xy = 3

 Author: Archit3110 [ 24 Dec 2018, 02:09 ] Post subject: Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3 Bunuel wrote:What is the value of (x - 1)(y + 1) ?(1) x + y = 4(2) xy = 3#1: x+y= 4x,y can be (1,3) ( 2,2,) (4,0)insufficient#2 xy=3 3,1 , 1/3*9 ... in sufficient on combining we get (1,3 ) as the only number which would be sufficient .. IMO C answer is C over E so because definite values of x & y are not sure and we get two value s in (x - 1)(y + 1) on substitution of (3,1) or (1,3)

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