GMAT Club Forumhttps://gmatclub.com:443/forum/ The measure of angle MKL is how many degrees greater than the measurehttps://gmatclub.com/forum/the-measure-of-angle-mkl-is-how-many-degrees-greater-than-the-measure-310954.html Page 1 of 1

 Author: kendrikFROMkenya [ 20 Nov 2019, 08:21 ] Post subject: The measure of angle MKL is how many degrees greater than the measure Attachment: File comment: Question DS geom.png [ 36.02 KiB | Viewed 2759 times ]

 Author: chetan2u [ 20 Nov 2019, 20:03 ] Post subject: The measure of angle MKL is how many degrees greater than the measure kendrikFROMkenya wrote:Attachment:DS geom.pngStatement I Triangle MJK is equilateral. So $$\angle{MKJ}=\angle{MJK}=60$$, and angle MKJ+MKL=180....MKL=180-60=120..Answer 120-60=60Sufficient Statement IIThe Sum of the measure of MKJ and MJK is 120.Now $$\angle{MKL} = 180-\angle{MKJ}$$, and $$\angle{MKJ}+\angle{MJK}=120$$......$$\angle{MKJ}=120-\angle{MJK}$$..$$\angle{MKL} = 180-\angle{MKJ}=180-(120-\angle{MJK})=60+\angle{MJK}..........\angle{MKL} -\angle{MJK}=60$$D

 Author: unraveled [ 20 Nov 2019, 21:55 ] Post subject: The measure of angle MKL is how many degrees greater than the measure chetan2u wrote:kendrikFROMkenya wrote:Attachment:DS geom.pngStatement I Triangle MJK is equilateral. So $$\Angle{MKJ}=\angle{MJK}=60$$, and angle MKJ+MKL=180....MKL=180-60=120..Answer 120-60=60Sufficient Statement IIThe Sum of the measure of MKJ and MJK is 120.This basically means MKJ is an equilateral triangle. Hence answer is 60 as shown in statement IDNowhere it is mentioned that MJ = MK, a prerequisite so that $$\angle{MKJ}=\angle{MJK}=60$$ and Statement II be sufficient. Otherwise,$$\angle{MKJ}+\angle{MJK}=120$$ when $$\angle{MJK}=50$$ and $$\angle{MKJ}=70$$OR $$\angle{MJK}=30$$ and $$\angle{MKJ}=90$$Many possibilities exists hence statement II is not sufficient.Should not the answer be A. chetan2u Can you help me understand if am correct.

 Author: chetan2u [ 20 Nov 2019, 22:06 ] Post subject: The measure of angle MKL is how many degrees greater than the measure lnm87 wrote:chetan2u wrote:kendrikFROMkenya wrote:Attachment:DS geom.pngStatement I Triangle MJK is equilateral. So $$\Angle{MKJ}=\angle{MJK}=60$$, and angle MKJ+MKL=180....MKL=180-60=120..Answer 120-60=60Sufficient Statement IIThe Sum of the measure of MKJ and MJK is 120.This basically means MKJ is an equilateral triangle. Hence answer is 60 as shown in statement IDNowhere it is mentioned that MJ = MK, a prerequisite so that $$\angle{MKJ}=\angle{MJK}=60$$ and Statement II be sufficient. Otherwise,$$\angle{MKJ}+\angle{MJK}=120$$ when $$\angle{MJK}=50$$ and $$\angle{MKJ}=70$$OR $$\angle{MJK}=30$$ and $$\angle{MKJ}=90$$Many possibilities exists hence statement II is not sufficient.Should not the answer be A. chetan2u Can you help me understand if am correct.Hi, lnm87, I have just added a bit of explanation in my earlier post on why statement II is also sufficient.

 Author: pllktyl [ 20 Nov 2019, 22:12 ] Post subject: Re: The measure of angle MKL is how many degrees greater than the measure solution not correct. now I am skeptical of my verbal prep on gmat club.

 Author: unraveled [ 20 Nov 2019, 22:24 ] Post subject: Re: The measure of angle MKL is how many degrees greater than the measure chetan2u wrote:lnm87 wrote:Nowhere it is mentioned that MJ = MK, a prerequisite so that $$\angle{MKJ}=\angle{MJK}=60$$ and Statement II be sufficient. Otherwise,$$\angle{MKJ}+\angle{MJK}=120$$ when $$\angle{MJK}=50$$ and $$\angle{MKJ}=70$$OR $$\angle{MJK}=30$$ and $$\angle{MKJ}=90$$Many possibilities exists hence statement II is not sufficient.Should not the answer be A. chetan2u Can you help me understand if am correct.Hi, lnm87, I have just added a bit of explanation why statement II is also sufficient.PLease revert if any problem.My bad. I actually inferred wrongly. I thought that variations in angles(MJK or MKJ) would invalidate the statement II as sufficient but actually forgot that points M and J would act as hinges to direct other angles.Sorry to bother you for such pity queries.Thanks

 Author: chetan2u [ 21 Nov 2019, 00:05 ] Post subject: Re: The measure of angle MKL is how many degrees greater than the measure pllktyl wrote:solution not correct. now I am skeptical of my verbal prep on gmat club.Firstly, this question has hardly anything to do with verbal prep. It is simply addition of angles of the triangle, so why would someone get verbal prep into it!Secondly, why is the solution incorrect? Would request you to be more specific, so that everyone can benefit.

 Author: kendrikFROMkenya [ 21 Nov 2019, 07:49 ] Post subject: Re: The measure of angle MKL is how many degrees greater than the measure lnm87 wrote:chetan2u wrote:kendrikFROMkenya wrote:Attachment:DS geom.pngStatement I Triangle MJK is equilateral. So $$\Angle{MKJ}=\angle{MJK}=60$$, and angle MKJ+MKL=180....MKL=180-60=120..Answer 120-60=60Sufficient Statement IIThe Sum of the measure of MKJ and MJK is 120.This basically means MKJ is an equilateral triangle. Hence answer is 60 as shown in statement IDYou cant assume the two angles are equal based on statement (2).Nowhere it is mentioned that MJ = MK, a prerequisite so that $$\angle{MKJ}=\angle{MJK}=60$$ and Statement II be sufficient. Otherwise,$$\angle{MKJ}+\angle{MJK}=120$$ when $$\angle{MJK}=50$$ and $$\angle{MKJ}=70$$OR $$\angle{MJK}=30$$ and $$\angle{MKJ}=90$$Many possibilities exists hence statement II is not sufficient.Should not the answer be A. chetan2u Can you help me understand if am correct.

 Author: bumpbot [ 26 Dec 2022, 07:17 ] Post subject: Re: The measure of angle MKL is how many degrees greater than the measure Hello from the GMAT Club BumpBot!Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

 Page 1 of 1 All times are UTC - 8 hours [ DST ] Powered by phpBB © phpBB Grouphttp://www.phpbb.com/