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Walking at 5/6 of its usual speed, a train is 10 minutes too

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Walking at 5/6 of its usual speed, a train is 10 minutes too  [#permalink]

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New post 24 Apr 2011, 15:23
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Question Stats:

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Walking at 5/6 of its usual speed, a train is 10 minutes too late. What is usual time to cover the journey?

A. 70 minutes
B. 2 hours
C. 2/3 hours
D. 5/6 hours
E. 85 minutes

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Re: Journey  [#permalink]

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New post 25 Apr 2011, 10:07
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It was fairly short Mr. Subhashghosh!

But I approached this question as stated below,

New time must be 6/5 of old time (t) as the speed was reduced to 5/6 of the old speed (s)

Thus,

6/5(t) - t = 10
1/5t=10
t= 50 minutes
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Re: Journey  [#permalink]

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New post 24 Apr 2011, 15:57
vijayahir wrote:
Walking at 5/6 of its usual speed, a train is 10 minutes too late.what is usual time to cover the journey?

A. 70 minutes
B. 2 hours
C. 2/3 hours
D. 5/6 hours
E. 85 minutes


let Speed be S and Time to cover the journey be T

S * T = D (distance of journey) --- 1

now as per the question stem we have

(5/6)S * (T + 10) = D ----2

Equating Value of D from (1) in (2) we get T = 50mins or 5/6hrs .

Ans D
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Re: Journey  [#permalink]

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New post 24 Apr 2011, 16:02
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Its an easy question but answer choices made it bit interesting..
Kp you have got the right answer & I would have solved it the same way as you have on gmat but I have got an alternative explanation which will give the answer in around 20-30 sec!! :P

Let's see what others come up with..I will reveal my alternate approach soon!!
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Re: Journey  [#permalink]

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New post 25 Apr 2011, 04:02
5v/6 * (t+10) = vt

5t/6 + 50/6 = t

=> t = 50 min

=> t = 50/60 hrs = 5/6 hrs

Answer - D
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Re: Journey  [#permalink]

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New post 25 May 2011, 23:09
time and speed have inverse ratio's.
meaning 6/5 is the new time.

hence 6/5 t1 - t1 = 10 giving t1 = 50 min = 5/6 hrs.
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Re: Journey  [#permalink]

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New post 31 Dec 2013, 10:24
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MSDHONI wrote:
Walking at 5/6 of its usual speed, a train is 10 minutes too late.what is usual time to cover the journey?

A. 70 minutes
B. 2 hours
C. 2/3 hours
D. 5/6 hours
E. 85 minutes


Preferred approach for this one is the use of ratios as suggested by Karishma

So if train walks at 5/6 of usual speed, it is going to take 6/5 of its time

If its 10 minutes late then 1/5x =10

So x = 50 minutes = 5/6 hours

Hope it helps
Cheers!
J :)
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Re: Walking at 5/6 of its usual speed, a train is 10 minutes too  [#permalink]

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New post 18 May 2014, 08:12
MSDHONI wrote:
Walking at 5/6 of its usual speed, a train is 10 minutes too late.what is usual time to cover the journey?

A. 70 minutes
B. 2 hours
C. 2/3 hours
D. 5/6 hours
E. 85 minutes


"Walking at 5/6 of its usual speed, a train is 10 minutes too late."

On the lighter side, I wonder, since when the trains started walking ! ;-)
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Re: Walking at 5/6 of its usual speed, a train is 10 minutes too  [#permalink]

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New post 21 May 2014, 06:03
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Let usual speed is v and distance is d

usual time = d/v

at 5v/6, time = d/(5v/6) = 6d/5v

since at 5v/6, train is 10 min late

6d/5v - d/v = 10 min

d/5v = 10 min

d/v = 50 min

usual time = 50 min = 50/60 = 5/6 hr. Answer is D
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Re: Walking at 5/6 of its usual speed, a train is 10 minutes too  [#permalink]

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New post 28 Feb 2018, 10:40
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Distance = Rate * Time

The distance is the same in both scenarios, so:
5/6r * (t+10) = tr (divide by r)
5/6 * (t+10) = t
5/6 t + 50/6 = 6/6t
50/6 = 1/6t
t = 50

Answer is D!
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Re: Walking at 5/6 of its usual speed, a train is 10 minutes too &nbs [#permalink] 28 Feb 2018, 10:40
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