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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # We define that [x] is the least integer greater than of equal to x.

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Intern  B
Joined: 18 Apr 2013
Posts: 33
We define that [x] is the least integer greater than of equal to x.  [#permalink]

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6 00:00

Difficulty:   45% (medium)

Question Stats: 61% (01:42) correct 39% (01:24) wrong based on 121 sessions

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We define that [x] is the least integer greater than of equal to x. [x+1]=?
1) [x] =1
2) [2x]=1
Director  V
Joined: 04 Dec 2015
Posts: 738
Location: India
Concentration: Technology, Strategy
WE: Information Technology (Consulting)
Re: We define that [x] is the least integer greater than of equal to x.  [#permalink]

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roastedchips wrote:
We define that [x] is the least integer greater than of equal to x. [x+1]=?
1) [x] =1
2) [2x]=1

1) $$[x] =1$$

$$x = 1$$

$$[x+1]= [1 + 1] =2$$

Hence I is Sufficient.

2) $$[2x]=1$$

$$2x = 1 => x = \frac{1}{2}$$

$$[x]$$ is the least integer greater than of equal to $$x$$. Therefore $$x = 1$$.

$$[x+1]= [1 + 1] =2$$

Hence II is Sufficient.

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Please Press "+1 Kudos" to appreciate. Manager  D
Joined: 17 May 2015
Posts: 246
Re: We define that [x] is the least integer greater than of equal to x.  [#permalink]

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roastedchips wrote:
We define that [x] is the least integer greater than of equal to x. [x+1]=?
1) [x] =1
2) [2x]=1

Hi,

From St(1), we have 0 < x <= 1 => least integer of x+1 = 2 Definite answer.

From St(2), we have 0 < x <= 1/2 => least integer of x+1 = 2 Definite answer.

Thanks.
Intern  S
Joined: 11 Aug 2016
Posts: 46
Location: India
Concentration: Operations, General Management
Schools: HBS '18, ISB '17, IIMA
GMAT 1: 710 Q49 V38 GPA: 3.95
WE: Design (Manufacturing)
Re: We define that [x] is the least integer greater than of equal to x.  [#permalink]

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roastedchips wrote:
We define that [x] is the least integer greater than of equal to x. [x+1]=?
1) [x] =1
2) [2x]=1

Let us analyze each statement

Statement 1:
$$[x]=1$$
$$0<x<=1$$
$$1<x+1<=2$$ (Adding 1 throughout the inequality)
We know that x+1 will be greater than 1 and less than/equal to 2. So the least integer greater than or equal to $$x+1$$ is 2.
Hence sufficient.

Statement 2:
$$[2x]=1$$
$$0<2x<=1$$
$$0<x<=0.5$$ (Dividing by 2 throughout the inequality)
$$1<x+1<=1.5$$ (Adding 1 throughout the inequality)
We know $$x+1$$ will be greater than 1 and less than/equal to 1.5. So the least integer greater than or equal to $$x+1$$ is 2
Hence sufficient

Hit kudos if you like the explanation Manager  S
Joined: 11 Jun 2018
Posts: 100
Schools: DeGroote "22 (S)
GMAT 1: 500 Q39 V21 Re: We define that [x] is the least integer greater than of equal to x.  [#permalink]

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@chetan2u:-what does greater than of equal to x mean? Re: We define that [x] is the least integer greater than of equal to x.   [#permalink] 22 Jan 2019, 10:08
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# We define that [x] is the least integer greater than of equal to x.  