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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Let Bruce complete 1 unit of work per hr (as we already know he took 20 hrs)
and Wendy x units of work per hour

So total Work = 20 units (1 unit *20 hrs)

Work done by Wendy in 4 hrs= 4x
Work done by Wendy and Bruce in 2 hrs = 2x+ 2
Hence, Total work done = 4x +2x +2=6x+2

Equating, 6x+2=20
or 6x=18
or x=3
Now we know, Wendy completed 3 units of work per hour
hence to complete 20 units of work, she would need 20/3 hrs

Correct Option (C)

+1 Kudos if you find my approach useful.
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Let Wendy take 'w' hrs to complete the work
Bruce takes 20 hrs to complete the work.

Work done in 1 hr is 1/w & 1/20 by Wendy & Bruce respectively.

Therefore,
Work done by Wendy in 4 hrs = 4*(1/w) ------------- (1)
Work done by Wendy & Bruce in 2 hrs = 2*(1/w + 1/20) ------------ (2)

From 1 & 2, work done in 1 hour is 1 unit, i.e
4/w + 2/w + 2/20 = 1.
Solving the above equation, we get w = 20/3

Hence C !!
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Bunuel wrote:
Wendy begins sanding a kitchen floor by herself and works for 4 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?

A. 9/80 hours
B. 3/20 hours
C. 20/3 hours
D. 80/9 hours
E. 10 hours

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6/W + 2/B= 1
Now B=20

6/W=1-1/10
6/W=9/10
W=60/9=20/3

Answer: C
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Bunuel wrote:
Wendy begins sanding a kitchen floor by herself and works for 4 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?

A. 9/80 hours
B. 3/20 hours
C. 20/3 hours
D. 80/9 hours
E. 10 hours

Kudos for a correct solution.


one method has been as discussed above..

the other could be..
bruce can do it in 20h.. so in two hrs he will do 2/20th of work=1/10 of work
so wendy does 9/10 of work in 6 hrs..
wendy will complete the work in 6*10/9=20/3 hrs
C

Also here the choices are so apart that one can eliminate all but the correct one..
since W works for 6 days and b for 2 days.. ..
A and B are less than 1 day , can be eliminated straightway..
E and D are 9 and 10 days.. which would enable both to finsh the work in 6 to 7 days , which cannot be correct..
only C is close by..
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Bunuel wrote:
Wendy begins sanding a kitchen floor by herself and works for 4 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?

A. 9/80 hours
B. 3/20 hours
C. 20/3 hours
D. 80/9 hours
E. 10 hours

Kudos for a correct solution.


It took me a long time to solve this, on the real exam I probably would just have skipped it. Set up a Rate x Time = Work Table:

Wendy's Rate = X, | Time worked = 4 | Work done = 4X

Bruce's Rate = 2 | Time Worked = 20 | Work done 40 (40 is a nice number to plug in, since there is no actual work given in the question).

Combined Rate = 2+x | Time Worked = 2 | Work done = 40-4x > we can solve this 2x +4 = 40 - 4x >>> 6x = 36 >>> x = 6

Therefore Wendy's Rate is 6/h

If she does the job on her own, we have 40/6 = 6.666666

Answer Choice C
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Bunuel wrote:
Wendy begins sanding a kitchen floor by herself and works for 4 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?

A. 9/80 hours
B. 3/20 hours
C. 20/3 hours
D. 80/9 hours
E. 10 hours

Kudos for a correct solution.


Let, Total Work Units = 60

Let, Work done by Wendy in an hour = W units
i.e., Work done by Wendy in 4 hour = 4W units

Since Bruce finish the entire work in 20 hours
therefore, Work done by Bruce in an hour = 60/20 = 3 units

i.e., Work done by Wendy and Bruce together in 1 hour = (W+3) units
i.e., Work done by Wendy and Bruce together in 2 hour = 2(W+3) units

Total Work = 60 = 4W + 2(W+3)
i.e. 6W + 6 = 60
i.e. 6W = 54
i.e. W = 9 Units

Total Time taken by Wendy to finish the work herself = 60/9 = 20/3 hours

Answer: Option C
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
Bunuel wrote:
Wendy begins sanding a kitchen floor by herself and works for 4 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?

A. 9/80 hours
B. 3/20 hours
C. 20/3 hours
D. 80/9 hours
E. 10 hours

Kudos for a correct solution.


we are told that W worked for 4 hours...
then B joined. together worked for 2 hours.
B alone finished the work in 20 hours.
his rate is 1/20
in 2 hours, he alone gets 1/10 work done.
it means that W in 6 hours did 9/10 work.

we have time, we have work completed. we can find rate.
9/10 * 1/6 = 9/60 = 3/20. this is W's rate.
therefore, she can do 1 job in 20/3 hours.

answer is C.
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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Re: Wendy begins sanding a kitchen floor by herself and works for 4 hours. [#permalink]
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