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What is the approximate value of the sum of this sequence:

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Manager
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What is the approximate value of the sum of this sequence: [#permalink]

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02 May 2007, 05:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the approximate value of the sum of this sequence:

S=1/32 + 1/33 + ... +1/64

Is there any shortcut?
Manager
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02 May 2007, 22:50
You've got a Harmonic Progression when the reciprocals of the values of your series became an Arithmetic Progression. In your case the AP is
32, 33, 34,....64

The only way I know to solve these is to find a range within which the sum will be. Here's how:

Find the total number of terms in your series. Here's how I do it:
tn = t1 + (n-1)d
64 = 32 + (n-1)1
n = 33

Add the first term and the last term to itself n number of times (33 here)
Thats 33(1/32) & 33(1/64)

So the sum of the series will be between 33/64 & 33/32.
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03 May 2007, 13:51
i really wouldn't know how to solve this either, i'm curious to see the answer choices, but i would take this as a simple estimation problem

S=1/32 + 1/33 + ... +1/64

so you're adding a bunch of tiny fractions that are roughly equal to:

8/30 + 10/40 + 10/50 + 5/60

so you can add them rather quickly..

8/30 + 1/4 + 1/5 + 5/60 ->

4/15 + 1/4 + 3/15 + 5/60 ->

16/60 + 1/4 + 12/60 + 5/60 ->

33/60 + 1/4 ->

roughly 1/2 + 1/4 = 3/4

and since everything was rounded down i'd look for an answer a little higher. i would hope this could get me in the ballpark of the answers but you'd really have to see the answer choices to know for sure

.. and thats my very simple minded attempt to solve that =)
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03 May 2007, 16:56
Why can't we use the sum of a sequence equation?

n(a1+an)/2

where n=the number of values
a1=the first value
an=the last value

If you plug everything in you get 33(1/32+1/64)/2

=33(32/64+1/64)/2
=33(33/64)/2
=999/64*1/2
=999/128
=approx 7.6

What's the OA and why can't we use this equation?

Thanks!
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04 May 2007, 05:25
Very impressive Bluebird. You ask a good question.
My quant teacher told me there were different rules for AP's, GP's and HP's. He told me while we can get an exact value for the sum of an AP or a GP, we can only get a range within which the value of the sum of an HP series will be.

Maybe someone else might be able to add more to this but this is all I can tell you on this subject.
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04 May 2007, 07:55
Thanks for the help vikramjit! This topic is not my strong suit so I appreciate the help! Does anyone else have any insight?

Thanks!
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04 May 2007, 08:12
can you explain the bold part ? (1/32 + 1/64) => 3/64 ? the sum of this series cannot be greater than 1...a helpful hint: make sure you logically check your answer too..

Bluebird wrote:
Why can't we use the sum of a sequence equation?

n(a1+an)/2

where n=the number of values
a1=the first value
an=the last value

If you plug everything in you get 33(1/32+1/64)/2

=33(32/64+1/64)/2
=33(33/64)/2
=999/64*1/2
=999/128
=approx 7.6

What's the OA and why can't we use this equation?

Thanks!
Manager
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05 May 2007, 08:01
You are absolutely right, fresinha12! I made a really stupid calculation error...sorry about that! If I fix the error I get 99/128=0.773.

B
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05 May 2007, 09:33
vikramjit_01 wrote:
You've got a Harmonic Progression when the reciprocals of the values of your series became an Arithmetic Progression. In your case the AP is
32, 33, 34,....64

The only way I know to solve these is to find a range within which the sum will be. Here's how:

Find the total number of terms in your series. Here's how I do it:
tn = t1 + (n-1)d
64 = 32 + (n-1)1
n = 33

Add the first term and the last term to itself n number of times (33 here)
Thats 33(1/32) & 33(1/64)

So the sum of the series will be between 33/64 & 33/32.

thanks vikramjit_01 for explanation it's simple and makes sence
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05 May 2007, 10:31
so i guess the answer will depend in the choices (i.e 0.8, 0.7, 0.6 or 0.75,0.77,0.72).
05 May 2007, 10:31
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