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# What is the area

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17 Mar 2018, 20:50
1
1
00:00

Difficulty:

(N/A)

Question Stats:

57% (00:49) correct 43% (00:01) wrong based on 7 sessions

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What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...

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Updated on: 17 Mar 2018, 22:20
|x/120| + |y/30| = 10
the equations are:
x/120 + y/30 = 10
-x/120 + y/30 = 10
x/120 - y/30 = 10
-x/120 - y/30 = 10

Area will be 4* area of triangles = 4*1/2*300*1200 =720000
Attachments

WhatsApp Image 2018-03-18 at 10.39.12.jpeg [ 111.16 KiB | Viewed 285 times ]

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Originally posted by gmatbusters on 17 Mar 2018, 22:03.
Last edited by gmatbusters on 17 Mar 2018, 22:20, edited 2 times in total.
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Joined: 02 Aug 2009
Posts: 7958

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17 Mar 2018, 22:09
What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...

gmatbusters, it will not be a rectangle, but a rhombus..
$$|\frac{x}{120}| + |\frac{y}{30}| = 10$$...
Put x as 0..
$$|\frac{y}{30}| = 10$$....... y=300 and -300
put y as 0
$$|\frac{x}{120}| = 10$$......x = 1200 and -1200
so our vertices are .. (0,300),(1200,0),(0,-300),(-1200,0)

area is $$\frac{product of diagonals}{2} = \frac{600*2400}{2} = 720000$$

E
Attachments

area12.png [ 5.61 KiB | Viewed 291 times ]

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Posts: 1256
Location: India
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WE: Business Development (Energy and Utilities)
Re: What is the area  [#permalink]

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17 Mar 2018, 22:40
Thanks Sir

I got it, as the diagonals are perpendicular, it is a rectangle.

chetan2u wrote:
What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...

gmatbusters, it will not be a rectangle, but a rhombus..
$$|\frac{x}{120}| + |\frac{y}{30}| = 10$$...
Put x as 0..
$$|\frac{y}{30}| = 10$$....... y=300 and -300
put y as 0
$$|\frac{x}{120}| = 10$$......x = 1200 and -1200
so our vertices are .. (0,300),(1200,0),(0,-300),(-1200,0)

area is $$\frac{product of diagonals}{2} = \frac{600*2400}{2} = 720000$$

E

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: What is the area   [#permalink] 17 Mar 2018, 22:40
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