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What is the area

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What is the area  [#permalink]

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New post 17 Mar 2018, 20:50
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Question Stats:

57% (00:49) correct 43% (00:01) wrong based on 7 sessions

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What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...

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What is the area  [#permalink]

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New post Updated on: 17 Mar 2018, 22:20
|x/120| + |y/30| = 10
the equations are:
x/120 + y/30 = 10
-x/120 + y/30 = 10
x/120 - y/30 = 10
-x/120 - y/30 = 10



Please see the sketch.

Area will be 4* area of triangles = 4*1/2*300*1200 =720000
Attachments

WhatsApp Image 2018-03-18 at 10.39.12.jpeg
WhatsApp Image 2018-03-18 at 10.39.12.jpeg [ 111.16 KiB | Viewed 285 times ]


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Originally posted by gmatbusters on 17 Mar 2018, 22:03.
Last edited by gmatbusters on 17 Mar 2018, 22:20, edited 2 times in total.
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What is the area  [#permalink]

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New post 17 Mar 2018, 22:09
Gladiator59 wrote:
What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...


gmatbusters, it will not be a rectangle, but a rhombus..
\(|\frac{x}{120}| + |\frac{y}{30}| = 10\)...
Put x as 0..
\(|\frac{y}{30}| = 10\)....... y=300 and -300
put y as 0
\(|\frac{x}{120}| = 10\)......x = 1200 and -1200
so our vertices are .. (0,300),(1200,0),(0,-300),(-1200,0)

area is \(\frac{product of diagonals}{2} = \frac{600*2400}{2} = 720000\)

E
Attachments

area12.png
area12.png [ 5.61 KiB | Viewed 291 times ]


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Re: What is the area  [#permalink]

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New post 17 Mar 2018, 22:40
Thanks Sir

I got it, as the diagonals are perpendicular, it is a rectangle.

chetan2u wrote:
Gladiator59 wrote:
What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?

A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000

Edit: Options updated...


gmatbusters, it will not be a rectangle, but a rhombus..
\(|\frac{x}{120}| + |\frac{y}{30}| = 10\)...
Put x as 0..
\(|\frac{y}{30}| = 10\)....... y=300 and -300
put y as 0
\(|\frac{x}{120}| = 10\)......x = 1200 and -1200
so our vertices are .. (0,300),(1200,0),(0,-300),(-1200,0)

area is \(\frac{product of diagonals}{2} = \frac{600*2400}{2} = 720000\)

E


--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.


If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: What is the area   [#permalink] 17 Mar 2018, 22:40
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