I got it, as the diagonals are perpendicular, it is a rectangle.
Gladiator59 wrote:
What is the area enclosed by the closed figure formed by the equation
|x/120| + |y/30| = 10 ?
A. 150,000
B. 240,000
C. 540,000
D. 180,000
E. 720,000
Edit: Options updated...
gmatbusters, it will not be a rectangle, but a rhombus..
\(|\frac{x}{120}| + |\frac{y}{30}| = 10\)...
Put x as 0..
\(|\frac{y}{30}| = 10\)....... y=300 and -300
put y as 0
\(|\frac{x}{120}| = 10\)......x = 1200 and -1200
so our vertices are .. (0,300),(1200,0),(0,-300),(-1200,0)
area is \(\frac{product of diagonals}{2} = \frac{600*2400}{2} = 720000\)
E
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