What is the area of four sided figure formed by the intersection of

We need to find the equation |2X| + |Y| = 6

Equation 1 : 2X + Y = 6 which is Y = -2X + 6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = 6 ) , ( X = 3 , Y = 0 )
Equation 2 : -2X - Y = 6 which is Y = -2X - 6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = -6 ) , ( X = -3 , Y = 0 )

From here we know the intersects of the lines ,
Using area of triangles = 0.5 * X * Y
= 0.5 * 3 * 6
= 9
Using symmetry 4 triangles = 9 * 4
= 36 .
Answer is D . ( Sketch a diagram to visualize it helps !! )

Is it correct if I assume that the area is the product of the following two equations?

2x+y=6
2x+y=-6

These are four equations. If you carefully observe these equations because of the way mod functions are plotted around y and x axis as opposite images, these four lines form a rhombus with diagonals of lengths as 6 and 12 (if x =0 then possible y values 0,6 and 0,-6) and then (if y =0 x intercepts at 3,0 and -3,0. Area of rhombus is 1/2 * (product of diagonals) = 1/2 * 12 *6 = 36.

What's the fastest way to solve this?

I took almost 4 mins. First opened mods and found the 4 equations. Then found 2 points per equation. Then found area of one triangle and multiplied it by 4 (for area of the 4 triangles formed)

took me some time to draw some points...
but i believe the easiest way is:
x=0, then y=6 or -6.
y=0, x=3 or -3.
we get 4 similar 90 degrees triangles, with the 90 degree angle at the origin.
short leg is 3, long leg is 6.
area is leg*leg/2 = 18/2 = 9.
since we have 4 of these triangles, the area is 9*4 = 36.

D

Can someone give a diagrammatic answer to this? Would be really helpful to understand what kind of rhombus or square gets created :)

Please correct me if i am wrong.

|2x|+|y|=6

When, x=2, y=2,-2 Points are (2,2) and (2,-2)
When, x=-2 y=2,-2 Points are (-2,2) and (-2,-2)

I get a square with an area of (4x4) =16.

It's a rhombus. Check here: https://gmatclub.com/forum/what-is-the- ... l#p1910705

From the equation, we know that for all the four lines:
y-intercept is either +6 or -6
&
x-intercept is either +3 or -3

So, the shape of the quadrilateral is a rhombus with one diagnol length as 12 (from +6 to -6) and other diagnol length as 6 (from +3 to -3)

Therefore, Area of Rhombus= (d1xd2)/2 = (12x6)/2 = 36.

Ans D.

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By drawing a diagram we see that we have a rhombus .We know that each side of the rhombus is X so \(Area=base*hight=x^2\) must be a perfect square of a number D. \(36=6^2\) fits

Can't (1,4) (-1,4)
(2,2), (-2,-2) be used to solve the problem? Maybe I didn't understand the question properly...

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