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What is the area of four sided figure formed by the intersection of
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09 Feb 2015, 04:08
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What is the area of four sided figure formed by the intersection of the set of lines represented by 2x + y = 6? A. 18 B. 24 C. 30 D. 36 E. 48
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19 Aug 2017, 06:26
Madhavi1990 wrote: What is the area of four sided figure formed by the intersection of the set of lines represented by 2x + y = 6?
A. 18 B. 24 C. 30 D. 36 E. 48
Can someone give a diagrammatic answer to this? Would be really helpful to understand what kind of rhombus or square gets created :) Check below: Similar questions to practice: http://gmatclub.com/forum/theareaboun ... 93103.htmlhttp://gmatclub.com/forum/inthexypl ... 86549.htmlhttp://gmatclub.com/forum/ifequationx ... 01963.htmlhttp://gmatclub.com/forum/whatisthea ... 50487.htmlhttp://gmatclub.com/forum/newsetofmi ... l#p1208441http://gmatclub.com/forum/theareaboun ... 86595.htmlhttp://gmatclub.com/forum/ifequationx ... 26117.htmlhttp://gmatclub.com/forum/ifequationx ... 01963.htmlAttachment:
MSP176123adgic2i11338i000006b1h17e7337i675d.gif [ 3.94 KiB  Viewed 6915 times ]
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Re: What is the area of four sided figure formed by the intersection of
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Updated on: 05 Oct 2016, 13:41
Turkish wrote: What is the area of four sided figure formed by the intersection of the set of lines represented by 2x+y = 6?
1. 18 2.24 3.30 4.36 5.48 we just need four XY pair to define the foursided figure. Lets works with the concept of X and Y intercepts When x=0; then y=6 .. right y=6 and 6 ; XY pairs are {0,6} and {0,6} when y=0 then 2x= 6 x=3 and 3 ; The XY pairs are (3,0 and 3,0) When you plot these XY pairs you will see that you get a diamond shaped figure (an upright RHOMBUS ) which can be divided into 2 equal triangles. the base of these two triangles is the xaxis Now area of a triangle = 1/2 * base * height = 1/2 * 6*6 (the distance between 3 and 3 is 6) and the height is 60 = 6 Therefore Area of the triangle = \(\frac{1}{2}*36\) =====>18 There are 2 such triangle Total area = 2*18 =36 ANSWER IS D
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Originally posted by LogicGuru1 on 24 Jul 2016, 23:29.
Last edited by LogicGuru1 on 05 Oct 2016, 13:41, edited 1 time in total.




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Re: What is the area of four sided figure formed by the intersection of
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30 Sep 2016, 07:23
Turkish wrote: What is the area of four sided figure formed by the intersection of the set of lines represented by 2x+y = 6?
1. 18 2.24 3.30 4.36 5.48 took me some time to draw some points... but i believe the easiest way is: x=0, then y=6 or 6. y=0, x=3 or 3. we get 4 similar 90 degrees triangles, with the 90 degree angle at the origin. short leg is 3, long leg is 6. area is leg*leg/2 = 18/2 = 9. since we have 4 of these triangles, the area is 9*4 = 36. D
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Re: What is the area of four sided figure formed by the intersection of
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09 Feb 2015, 05:37
We need to find the equation 2X + Y = 6
Equation 1 : 2X + Y = 6 which is Y = 2X + 6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = 6 ) , ( X = 3 , Y = 0 ) Equation 2 : 2X  Y = 6 which is Y = 2X  6 . Points where this lines intersects the X and Y axis ( X = 0 , Y = 6 ) , ( X = 3 , Y = 0 )
From here we know the intersects of the lines , Using area of triangles = 0.5 * X * Y = 0.5 * 3 * 6 = 9 Using symmetry 4 triangles = 9 * 4 = 36 . Answer is D . ( Sketch a diagram to visualize it helps !! )



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Re: What is the area of four sided figure formed by the intersection of
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30 Jun 2016, 22:50
Is it correct if I assume that the area is the product of the following two equations?
2x+y=6 2x+y=6



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Re: What is the area of four sided figure formed by the intersection of
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03 Jul 2016, 01:03
These are four equations. If you carefully observe these equations because of the way mod functions are plotted around y and x axis as opposite images, these four lines form a rhombus with diagonals of lengths as 6 and 12 (if x =0 then possible y values 0,6 and 0,6) and then (if y =0 x intercepts at 3,0 and 3,0. Area of rhombus is 1/2 * (product of diagonals) = 1/2 * 12 *6 = 36.



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Re: What is the area of four sided figure formed by the intersection of
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15 Aug 2016, 05:28
What's the fastest way to solve this?
I took almost 4 mins. First opened mods and found the 4 equations. Then found 2 points per equation. Then found area of one triangle and multiplied it by 4 (for area of the 4 triangles formed)



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Re: What is the area of four sided figure formed by the intersection of
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19 Aug 2017, 06:20
Can someone give a diagrammatic answer to this? Would be really helpful to understand what kind of rhombus or square gets created :)



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Re: What is the area of four sided figure formed by the intersection of
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05 Oct 2017, 19:52
Please correct me if i am wrong. 2x+y=6 When, x=2, y=2,2 Points are (2,2) and (2,2) When, x=2 y=2,2 Points are (2,2) and (2,2) I get a square with an area of (4x4) =16.
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Re: What is the area of four sided figure formed by the intersection of
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05 Oct 2017, 21:02
Rishovnits wrote: Please correct me if i am wrong.
2x+y=6
When, x=2, y=2,2 Points are (2,2) and (2,2) When, x=2 y=2,2 Points are (2,2) and (2,2)
I get a square with an area of (4x4) =16. It's a rhombus. Check here: https://gmatclub.com/forum/whatisthe ... l#p1910705
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What is the area of four sided figure formed by the intersection of
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06 Oct 2017, 14:26
From the equation, we know that for all the four lines: yintercept is either +6 or 6 & xintercept is either +3 or 3
So, the shape of the quadrilateral is a rhombus with one diagnol length as 12 (from +6 to 6) and other diagnol length as 6 (from +3 to 3)
Therefore, Area of Rhombus= (d1xd2)/2 = (12x6)/2 = 36.
Ans D.
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What is the area of four sided figure formed by the intersection of
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12 Apr 2018, 14:54
Turkish wrote: What is the area of four sided figure formed by the intersection of the set of lines represented by 2x + y = 6?
A. 18 B. 24 C. 30 D. 36 E. 48 By drawing a diagram we see that we have a rhombus .We know that each side of the rhombus is X so \(Area=base*hight=x^2\) must be a perfect square of a number D. \(36=6^2\) fits
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Re: What is the area of four sided figure formed by the intersection of
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16 Oct 2018, 04:37
Turkish wrote: What is the area of four sided figure formed by the intersection of the set of lines represented by 2x + y = 6?
A. 18 B. 24 C. 30 D. 36 E. 48 Can't (1,4) (1,4) (2,2), (2,2) be used to solve the problem? Maybe I didn't understand the question properly...




Re: What is the area of four sided figure formed by the intersection of
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