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# What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11

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Intern
Joined: 05 Nov 2005
Posts: 34

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What is the average of 8a and 4b? 1. a+b=5 2. 2a+b=11 [#permalink]

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20 Nov 2005, 15:30
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Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11

Kudos [?]: 13 [0], given: 0

VP
Joined: 06 Jun 2004
Posts: 1050

Kudos [?]: 181 [0], given: 0

Location: CA

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20 Nov 2005, 15:34

(8a+4b)/2 ==> 4(2a+b)/2

(1) We do not know the values of a and b. Insufficient.

(2) 2a+b = 11, we know the average is 4(11)/2. Sufficient.

Kudos [?]: 181 [0], given: 0

Senior Manager
Joined: 15 Apr 2005
Posts: 414

Kudos [?]: 17 [0], given: 0

Location: India, Chennai

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21 Nov 2005, 01:24
faisalt wrote:
Q1. What is the average of 8a and 4b?
1. a+b=5
2. 2a+b=11

Its B.
Multiply both sides of statemen2 by 4 we get
8a + 4b = 44 Hence the answer.

Kudos [?]: 17 [0], given: 0

Director
Joined: 27 Jun 2005
Posts: 502

Kudos [?]: 171 [0], given: 0

Location: MS

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21 Nov 2005, 12:40
one more vote for B

Q1. What is the average of 8a and 4b?
1. a+b=5

We need to know the sum of 8a+4b , can not be calculated from a+b. Hence Insuff

2. 2a+b=11

8a+4b= 4(2a+b)=4*11

average 4*11/2

Suff

so B

Kudos [?]: 171 [0], given: 0

Current Student
Joined: 29 Jan 2005
Posts: 5206

Kudos [?]: 434 [0], given: 0

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23 Nov 2005, 06:09
1. 8a+4b cannot determine a+b in the sum so insufficent

2. 4(2a+b); substitute 11--->4(11)=44 sufficient

(B)

Kudos [?]: 434 [0], given: 0

23 Nov 2005, 06:09
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