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# What is the difference between the maximum and the minimum value of x/

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What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 02:49
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What is the difference between the maximum and the minimum value of x/y for which (x − 2)^2 = 9 and (y − 3)^2 = 25?

(A) −15/8
(B) 3/4
(C) 9/8
(D) 19/8
(E) 25/8
[Reveal] Spoiler: OA

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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 03:04
x= -1, 5
y= -2, 8
Max x/y = 5/8 ; Min x/y = -5/2
Difference = 25/8
E.

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What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 03:07
Given data : $$(x − 2)^2 = 9$$ and $$(y − 3)^2 = 25$$

To find the difference between the maximum and minimum values of \frac{x}{y}

$$(x − 2)^2 = 9 -> (x-2) = 3$$ or $$(x-2) = -3$$
Maximum value of x : 5
Minimum value of x : -1

$$(y − 3)^2 = 25 -> (y-3) = 5$$ or $$(y-3) = -5$$
Maximum value of y : 8
Minimum value of y : -2

Maximum value of $$\frac{x}{y} = \frac{5}{8}$$, Minimum value of $$\frac{x}{y} = \frac{5}{-2}$$

Difference is $$\frac{5}{8} - (\frac{-5}{2}) = \frac{25}{8}$$(Option E)
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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 05:43
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pushpitkc wrote:
Given data : $$(x − 2)^2 = 9$$ and $$(y − 3)^2 = 25$$

To find the difference between the maximum and minimum values of \frac{x}{y}

$$(x − 2)^2 = 9 -> (x-2) = 3$$ or $$(x-2) = -3$$
Maximum value of x : 5
Minimum value of x : -1

$$(y − 3)^2 = 25 -> (y-3) = 5$$ or $$(y-3) = -5$$
Maximum value of y : 8
Minimum value of y : -2

Maximum value of $$\frac{x}{y} = \frac{5}{8}$$, Minimum value of $$\frac{x}{y} = \frac{5}{-2}$$

Difference is $$\frac{5}{8} - (\frac{-5}{2}) = \frac{25}{8}$$(Option D)

It's option E
I used the same method

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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 05:48
MvArrow wrote:
pushpitkc wrote:
Given data : $$(x − 2)^2 = 9$$ and $$(y − 3)^2 = 25$$

To find the difference between the maximum and minimum values of \frac{x}{y}

$$(x − 2)^2 = 9 -> (x-2) = 3$$ or $$(x-2) = -3$$
Maximum value of x : 5
Minimum value of x : -1

$$(y − 3)^2 = 25 -> (y-3) = 5$$ or $$(y-3) = -5$$
Maximum value of y : 8
Minimum value of y : -2

Maximum value of $$\frac{x}{y} = \frac{5}{8}$$, Minimum value of $$\frac{x}{y} = \frac{5}{-2}$$

Difference is $$\frac{5}{8} - (\frac{-5}{2}) = \frac{25}{8}$$(Option D)

It's option E
I used the same method

Damn, I have to proof read my solution.
Thanks a ton. Made the necessary change.
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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 08:33
Taking square root on both sides and considering both positive and negative roots into consideration, x= -1, 5

Similarly, Taking square root on both sides and considering both positive and negative roots into consideration, y= -2, 8

Four values of x/y are possible : (1/2), (-1/8), (5/-2) & (5/8).

Of these, Max x/y = 5/8 ; Min x/y = -5/2

Difference = 25/8

Option E is the answer.

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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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03 Jul 2017, 09:15
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If you solve respective equations for x and y, you will get as below.
X = 5 and -1
Y = 8 and -2
Just arrange all four combinations of x and y for our understanding of which is least and which is highest.

5/8, 5/-2, -1/8, -1/-2

Lowest (Most negative) is 5/-2 i.e. -2/5 and Highest is 5/8
So, 5/8 - ( -5/2) = 25/8
Hence answer is E.

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Re: What is the difference between the maximum and the minimum value of x/ [#permalink]

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12 Aug 2017, 21:44
pushpitkc wrote:
Given data : $$(x − 2)^2 = 9$$ and $$(y − 3)^2 = 25$$

To find the difference between the maximum and minimum values of \frac{x}{y}

$$(x − 2)^2 = 9 -> (x-2) = 3$$ or $$(x-2) = -3$$
Maximum value of x : 5
Minimum value of x : -1

$$(y − 3)^2 = 25 -> (y-3) = 5$$ or $$(y-3) = -5$$
Maximum value of y : 8
Minimum value of y : -2

Maximum value of $$\frac{x}{y} = \frac{5}{8}$$, Minimum value of $$\frac{x}{y} = \frac{5}{-2}$$

Difference is $$\frac{5}{8} - (\frac{-5}{2}) = \frac{25}{8}$$(Option E)

was thinking if we need to make x/y maximum, dont we have to divide x as max and y as min i.e 5/-2 and similarly for x/y to be min , x min. and y max i.e. -1/8 and then take the difference?

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Re: What is the difference between the maximum and the minimum value of x/   [#permalink] 12 Aug 2017, 21:44
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# What is the difference between the maximum and the minimum value of x/

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