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# What is the fastest way of doing this kinda problems.... How

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Senior Manager
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What is the fastest way of doing this kinda problems.... How [#permalink]

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02 Feb 2004, 21:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the fastest way of doing this kinda problems....

How many multiples of 5 are there among the integers 5 through 125 inclusive?

Vivek.
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"Start By Doing What Is Necessary ,Then What Is Possible & Suddenly You Will Realise That You Are Doing The Impossible"

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02 Feb 2004, 22:10
one can derive the following:

#multiples of n b/w x and y (inclusive) = 1 + [|x-y|/n] or [|x-y|/n] where | k | = absolute value of k, [k] = integral part of k.

Except for this being an algebraic forumation, this does not help one count.

Last edited by Zhung Gazi on 03 Feb 2004, 02:30, edited 2 times in total.

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03 Feb 2004, 00:42
You rock Zhung Gazi....

Thanks..

Vivek.
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03 Feb 2004, 08:55
is it 26..??
5+125/5..
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shubhangi

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03 Feb 2004, 12:34
Going by Zhung Gazi's formula...

#multiples of n b/w x and y (inclusive) = 1 + [|x-y|/n]

= 1+ [|5-125|/5]
= 1+ [120/5]
=1+24
= 25

Alternately....125/5=25... you got 26...that would mean you are considereing 0 as a miultiple of 5 too...but since the range starts from 5 ...the # of multiples are 25...

Vivek.
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03 Feb 2004, 12:34
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# What is the fastest way of doing this kinda problems.... How

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