It is currently 17 Oct 2017, 05:05

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the greatest distance between two points in a

Author Message
Director
Joined: 10 Feb 2006
Posts: 660

Kudos [?]: 619 [0], given: 0

What is the greatest distance between two points in a [#permalink]

### Show Tags

06 Jun 2008, 11:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the greatest distance between two points in a cylinder where the area of the base is 9pie and height is 5?
_________________

GMAT the final frontie!!!.

Kudos [?]: 619 [0], given: 0

Current Student
Joined: 28 Dec 2004
Posts: 3351

Kudos [?]: 319 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

06 Jun 2008, 11:42
What is the greatest distance between two points in a cylinder where the area of the base is 9pie and height is 5?

i believe the diag is the furthest 2 points..

so the base diameter is 6..so that would sqrt(61)

Kudos [?]: 319 [0], given: 2

Director
Joined: 10 Feb 2006
Posts: 660

Kudos [?]: 619 [0], given: 0

### Show Tags

06 Jun 2008, 11:58
can you elaborate ? Thanks
_________________

GMAT the final frontie!!!.

Kudos [?]: 619 [0], given: 0

SVP
Joined: 30 Apr 2008
Posts: 1868

Kudos [?]: 615 [0], given: 32

Location: Oklahoma City
Schools: Hard Knocks

### Show Tags

06 Jun 2008, 12:15
What is the greatest distance between two points in a cylinder where the area of the base is 9pie and height is 5?

The area of the base = $$9\pi$$

The formula for the area of a triangle = $$\pi * r^2$$
so if

$$\pi * r^2 = 9\pi$$
$$\pi$$ drops out from both sides

$$r^2 = 9$$
square root both sides to get r
$$r = 3$$

If the radius is 3, then diameter of the circle is 6. If the diagonal is the fartherst 2 points can be from each other, then we have a right traingle. The diameter of the circle is one base, and the height of the cylindar wall is the other base of the triangle. The hypotnuse is the diagonal (i.e., furthest distance 2 points can be from each other in a cylinder).

$$a^2 + b^2 = c^2$$
$$6^2 + 5^2 = c^2$$
$$36 + 25$$is$$61 so [m] 61 = c^2$$

$$c = \sqrt{61}$$
_________________

------------------------------------
J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a.

GMAT Club Premium Membership - big benefits and savings

Kudos [?]: 615 [0], given: 32

Re: cylinder   [#permalink] 06 Jun 2008, 12:15
Display posts from previous: Sort by