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# What is the largest prime factor of the sum of the series of

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Current Student
Joined: 29 Jan 2005
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What is the largest prime factor of the sum of the series of [#permalink]

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11 Dec 2005, 04:02
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What is the largest prime factor of the sum of the series of consecutive integers from 1 to 30, inclusive?

A. 31
B. 17
C. 13
D. 11
E. 5

Kudos [?]: 434 [0], given: 0

Director
Joined: 24 Oct 2005
Posts: 572

Kudos [?]: 76 [1], given: 0

Location: NYC

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11 Dec 2005, 04:05
1
KUDOS
sum of consecutive numbers. .
n*(n+1)/2

so. (30*31)/2

hence 31.. largest prime factor..at 5 in the morning. .
_________________

Success is my only option, failure is not -- Eminem

Kudos [?]: 76 [1], given: 0

VP
Joined: 20 Sep 2005
Posts: 1016

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13 Dec 2005, 15:21
Got 31 quickly but not as efficiently as bewakof.

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Senior Manager
Joined: 05 Oct 2005
Posts: 485

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13 Dec 2005, 16:26
lhotseface wrote:
Got 31 quickly but not as efficiently as bewakof.

Bewakoof is not all that bewakoof after all
(bewakoof = dumb in Hindi/Urdu)

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VP
Joined: 06 Jun 2004
Posts: 1050

Kudos [?]: 181 [0], given: 0

Location: CA
Re: PS Arithmetic progression [#permalink]

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13 Dec 2005, 23:32
GMATT73 wrote:
What is the largest prime factor of the sum of the series of consecutive integers from 1 to 30, inclusive?

A. 31
B. 17
C. 13
D. 11
E. 5

Sum = (# of integers) (average) = (30-1+1) (31/2) = 465 = 5*3*31

bewakoof, what are you doing up at 5am in the morning?

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Current Student
Joined: 29 Jan 2005
Posts: 5206

Kudos [?]: 434 [1], given: 0

Re: PS Arithmetic progression [#permalink]

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14 Dec 2005, 00:05
1
KUDOS
TeHCM wrote:
GMATT73 wrote:
What is the largest prime factor of the sum of the series of consecutive integers from 1 to 30, inclusive?

A. 31
B. 17
C. 13
D. 11
E. 5

Sum = (# of integers) (average) = (30-1+1) (31/2) = 465 = 5*3*31

bewakoof, what are you doing up at 5am in the morning?

5am? Give that man a 700!

Kudos [?]: 434 [1], given: 0

Senior Manager
Joined: 15 Apr 2005
Posts: 414

Kudos [?]: 17 [0], given: 0

Location: India, Chennai
Re: PS Arithmetic progression [#permalink]

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14 Dec 2005, 01:09
GMATT73 wrote:
What is the largest prime factor of the sum of the series of consecutive integers from 1 to 30, inclusive?

A. 31
B. 17
C. 13
D. 11
E. 5

sum = n/2(a+l), where a is the first term, l is the last term, and n is the number of terms in the series.
= 30/2(1+30)
= 15 * 31
31 is a prime number, and factor of 15*31, hence A.

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GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16723

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Re: What is the largest prime factor of the sum of the series of [#permalink]

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01 May 2017, 09:57
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: What is the largest prime factor of the sum of the series of   [#permalink] 01 May 2017, 09:57
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# What is the largest prime factor of the sum of the series of

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