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# What is the last two digits of (11^10) - 9 ?

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Senior Manager
Joined: 24 Apr 2016
Posts: 331
What is the last two digits of (11^10) - 9 ?  [#permalink]

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07 Mar 2017, 18:27
1
3
00:00

Difficulty:

35% (medium)

Question Stats:

71% (01:35) correct 29% (01:43) wrong based on 122 sessions

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What is the last two digits of (11^10) - 9 ?

A. 52

B. 72

C. 92

D. 02

E. 62
VP
Joined: 05 Mar 2015
Posts: 1004
Re: What is the last two digits of (11^10) - 9 ?  [#permalink]

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07 Mar 2017, 21:15
1
1
quantumliner wrote:
What is the last two digits of (11^10) - 9 ?

A. 52

B. 72

C. 92

D. 02

E. 62

11^0 = 01 (last 2 digits)
11^1= 11
11^2 =...21
11^3= ...31
...
11^9 = ...91
11^10 = ........01
11^11= ......11

the sequence of last two digits repeats as above
thus last to digit of 11^10 = 01 when subtacted by 9 ,last digit we obtain as 92

Ans C
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Location: India
Re: What is the last two digits of (11^10) - 9 ?  [#permalink]

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08 Mar 2017, 01:12
1
11^1 =11
11^2 = 121 last two is 21
11^3 = 1331 last two is 31
.
.
.
11^9 last two digit will be 91
11^10 last two digit will be 01

from abc01 subtract 9, we will get 92 as last two digit

Option C
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What is the last two digits of (11^10) - 9 ?  [#permalink]

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25 Jul 2018, 09:50
rohit8865 wrote:
quantumliner wrote:
What is the last two digits of (11^10) - 9 ?

A. 52

B. 72

C. 92

D. 02

E. 62

11^0 = 01 (last 2 digits)
11^1= 11
11^2 =...21
11^3= ...31
...
11^9 = ...91
11^10 = ........01
11^11= ......11

the sequence of last two digits repeats as above
thus last to digit of 11^10 = 01 when subtacted by 9 ,last digit we obtain as 92

Ans C

rohit8865 hey there how is it possible that $$11^0$$ has last 2 digits 01 whats the logic behind it ? looking at $$11^0$$ i simply see 11 last as two digits :D...

even if any number raised to exponent zero is 1 ,,,, but how about 0 01 ..it says $$11^0$$ has last 2 digits 01

should nt we start from here 11^1= 11 ? instead of $$11^0$$

perhaps you pushpitkc could explain
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Posts: 3325
Location: India
GPA: 3.12
Re: What is the last two digits of (11^10) - 9 ?  [#permalink]

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25 Jul 2018, 21:19
1
dave13 wrote:
rohit8865 wrote:
quantumliner wrote:
What is the last two digits of (11^10) - 9 ?

A. 52

B. 72

C. 92

D. 02

E. 62

11^0 = 01 (last 2 digits)
11^1= 11
11^2 =...21
11^3= ...31
...
11^9 = ...91
11^10 = ........01
11^11= ......11

the sequence of last two digits repeats as above
thus last to digit of 11^10 = 01 when subtacted by 9 ,last digit we obtain as 92

Ans C

rohit8865 hey there how is it possible that $$11^0$$ has last 2 digits 01 whats the logic behind it ? looking at $$11^0$$ i simply see 11 last as two digits :D...

even if any number raised to exponent zero is 1 ,,,, but how about 0 01 ..it says $$11^0$$ has last 2 digits 01

should nt we start from here 11^1= 11 ? instead of $$11^0$$

perhaps you pushpitkc could explain

Hey dave13

Any number, when raised to the power of 0 is 1, which can also be written as 00000001
Zero has no value when used before any number (That's the explanation that the last two digits of $$11^0$$ is 01)

This is also the reason for considering the pattern from 11^0!

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Re: What is the last two digits of (11^10) - 9 ? &nbs [#permalink] 25 Jul 2018, 21:19
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