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# What is the least possible distance between a point on the c

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Intern
Joined: 08 Mar 2011
Posts: 43

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What is the least possible distance between a point on the c [#permalink]

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21 Mar 2011, 21:40
1
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2
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Difficulty:

55% (hard)

Question Stats:

62% (01:35) correct 38% (01:56) wrong based on 95 sessions

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What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y=(3/4)x -3 ?

A:1.4
b:sqrt of 2
c:1.7
d:sqrt of 3
e:2.0

OPEN DISCUSSION OF THIS QUESTION IS HERE: what-is-the-least-possible-distance-between-a-point-on-the-92566.html
[Reveal] Spoiler: OA

Kudos [?]: 33 [1], given: 4

Director
Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
Posts: 871

Kudos [?]: 401 [7], given: 123

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21 Mar 2011, 21:53
7
KUDOS
First plot the line. The y intercept is (0,-3) the x intercept is (4,0)
The height of the triangle formed by the triangle with vertices (0,0),(0,-3),(4,0) is say h. It's area is 1/2*3*4=6. the hyp of the triangle is 5 (triplet 3:4:5).
Therefore 1/2*h*5=6 hence h =12/5=2.4
Now the min distaff between the circle and line is 2.4-radius. Radius is 1. Hence min distance is 1.4. A is the answer
asmit123 wrote:
What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y=(3/4)x -3 ?
A:1.4
b:sqrt of 2
c:1.7
d:sqrt of 3
e:2.0

Posted from my mobile device

Kudos [?]: 401 [7], given: 123

Intern
Joined: 08 Mar 2011
Posts: 43

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21 Mar 2011, 22:32
Thanks friend. That was very clear.

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22 Mar 2011, 01:14

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22 Mar 2011, 02:52
Excellent explanation gmat1220.

+1 to you.
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Kudos [?]: 600 [0], given: 40

Manager
Joined: 05 Jan 2011
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22 Mar 2011, 08:32
gmat1220 wrote:
First plot the line. The y intercept is (0,-3) the x intercept is (4,0)
The height of the triangle formed by the triangle with vertices (0,0),(0,-3),(4,0) is say h. It's area is 1/2*3*4=6. the hyp of the triangle is 5 (triplet 3:4:5).
Therefore 1/2*h*5=6 hence h =12/5=2.4
Now the min distaff between the circle and line is 2.4-radius. Radius is 1. Hence min distance is 1.4. A is the answer
asmit123 wrote:
What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y=(3/4)x -3 ?
A:1.4
b:sqrt of 2
c:1.7
d:sqrt of 3
e:2.0

Posted from my mobile device

Good Post thanks gmat1220

Kudos [?]: 196 [0], given: 8

Intern
Joined: 03 Apr 2012
Posts: 27

Kudos [?]: 13 [2], given: 10

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11 Aug 2013, 10:07
2
KUDOS
you can use the formula distance from a point (x", y") to a line ax+by+c is

|ax"+ by" +c |/ sqrt (a^2 + b ^2)

Here the equation of the circle x^2 + y^2 = 1 implies (x", y") = (0,0) and radius =1

Equation of the line y= 3/4 x- 3 writing it in ax+by+c=0 format 3/4x-y-3 = 0

| -3| / sqrt ( (3/4)^2 +1)

simplying you get 3 * 4/5
= 2.4

since radius is 1 distance from circle to line is 2.4 - 1 = 1.4

Kudos [?]: 13 [2], given: 10

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Posts: 42283

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Re: What is the least possible distance between a point on the c [#permalink]

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11 Aug 2013, 10:10
OPEN DISCUSSION OF THIS QUESTION IS HERE: what-is-the-least-possible-distance-between-a-point-on-the-92566.html
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Kudos [?]: 132929 [0], given: 12391

Senior Manager
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Re: What is the least possible distance between a point on the c [#permalink]

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11 Aug 2013, 14:44
Bunuel wrote:

......
very good collection.....
gmatclub.com is the only one and best....................
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Asif vai.....

Kudos [?]: 426 [0], given: 102

Re: What is the least possible distance between a point on the c   [#permalink] 11 Aug 2013, 14:44
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