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What is the maximum number of 1 3/4 foot pieces of wood that can be cu

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What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 12 Jan 2015, 11:10
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 12 Jan 2015, 11:35
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Answer D.

Each piece of wood can be cut in 6 pieces of 1.75 foot each. We get a remainder of 1.5 foot, so that doesn't count. 4 pieces of wood makes 24 1.75 foot pieces.
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 12 Jan 2015, 11:50
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Answer is D - 24.

Each piece of wood needs to be calculated separately as it isn't a continuous piece of wood.

So we have:
4 (12/1.75)
4 (6) - with a remainder but that doesn't count since it isn't 1.75
24 - D
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 12 Jan 2015, 12:29
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lets take one 12 feet wood.

we need to find max number of 7/4 feet length wood in one 12 feet wood.

with four pieces of 7/4 feet length wood, we would cover 7 feet of 12 leaving 5 remaining feet.
out of 5 feet we can get 2 more 7/4 foot. that is total of 6 per each 12 feet wood giving 24 for 4 pieces
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 14 Jan 2015, 00:31
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Answer = (D) 24

\(1\frac{3}{4} = \frac{7}{4}\)

Length available per piece \(= 12 = \frac{48}{4}\)

Denominators remaining same, number of pieces \(= \frac{48}{7} \approx{6}\) (Leave the decimal OR upper approximation)

Total pieces from 4 big pieces = 6*4 = 24
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu  [#permalink]

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New post 28 Jun 2017, 12:04
answer is D.

we can make 6 pieces from each of the 4 pieces of wood. 12/1.75 = 6 (integral value)

so total 6*4 =24
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Re: What is the maximum number of 1 3/4 foot pieces of wood that can be cu   [#permalink] 09 Aug 2019, 12:17
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