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What is the maximum possible number of chocolate bars per hour produce

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What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 26 Sep 2016, 03:29
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What is the maximum possible number of chocolate bars per hour produced by a machine?

(1) Currently, the machine produces 1,200 chocolate bars per hour.

(2) If the chocolate bar production rate is increased from half the machine's maximum rate by 300 chocolate bars per hour, the rate is increased by 25%.
[Reveal] Spoiler: OA

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Re: What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 26 Sep 2016, 18:40
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(1) Current rate is given, no mention of whether this is the max rate.
Not Sufficient.

(2) x be the max rate.
\(\frac{x}{2} +300 = 1.25 *x\)
\(x = 400\)
Sufficient.

Option B
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Re: What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 27 Sep 2016, 07:00
Its B
STatement 1 is clearly insufficient
sttement 2 : we can write from the question stem ass x/2+300=1.25∗x =>x=400 Sufficient
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What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 27 Sep 2016, 10:52
Statement 1 insuff no info on the rate
Statement 2 if x is the rate half of machines rate produces y work so x/2 = y now if we increase rate by 25% the work increases by 300 so 1.25x/2 = y+300
we can subtract the 2 equations to get .25x = 600 x= 2400 so I 1 hour maximum production is 2400
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Re: What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 27 Sep 2016, 10:55
deepthit wrote:
Its B
STatement 1 is clearly insufficient
sttement 2 : we can write from the question stem ass x/2+300=1.25∗x =>x=400 Sufficient


X cannot be 400 it would contradict statement 1
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What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 29 Nov 2016, 20:32
Hello Team
Engr2012, Bunuel, Vyshak, Abhishek009, Bunuel, mikemcgarry and other's
I too am confused by value of x so obtained. How can x < 1200 and still be considered as max rate? Is the value of 400 = deltax or change in x to be maximum ie max x = 1200 + 400 = 1600?

Can someone please clarify?
Thanks

This is what i did: relative increase in rate:
1.25x - x/2 = 300
5/4x - 2x/4 = 300
3x/4 = 300
x = 400
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What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 02 Dec 2016, 00:13
manishtank1988
Akuthiala

When you are considering the validity of option b, you need to forget about option a. Option B is sufficient because it allows you to calculate the maximum rate. It doesn't matter if rate (> < =) 1200
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Re: What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 31 Jan 2017, 21:27
we can all agree that statement 2 provides a way to solve the maximum rate, so answer is a good B.
However, can someone validate my interpretation of that statement?

(2) If the chocolate bar production rate is increased from half the machine's maximum rate by 300 chocolate bars per hour, the rate is increased by 25%.

Interpretation:--
Let C be the # of maximum number of chocolates produced per hour. So half the max rate is C/2 per hour. Now we need to add 300 to half the max rate and this whole thing is 25% greater than the existing rate of C/2

This way, we get
C/2 + 300 = 5/4(C/2)
=> 300 = (5/8-1/2)C=> C = 300*8 = 2400.

300 represents only 1/8 of the max rate. if we add 1/8 (0.125) to 1/2 (0.50) , this raises 1/2 by 25% up to 5/8 (0.625).
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What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 05 Feb 2017, 16:34
ajdse22 wrote:
we can all agree that statement 2 provides a way to solve the maximum rate, so answer is a good B.
However, can someone validate my interpretation of that statement?

(2) If the chocolate bar production rate is increased from half the machine's maximum rate by 300 chocolate bars per hour, the rate is increased by 25%.

Interpretation:--
Let C be the # of maximum number of chocolates produced per hour. So half the max rate is C/2 per hour. Now we need to add 300 to half the max rate and this whole thing is 25% greater than the existing rate of C/2

This way, we get
C/2 + 300 = 5/4(C/2)
=> 300 = (5/8-1/2)C=> C = 300*8 = 2400.

300 represents only 1/8 of the max rate. if we add 1/8 (0.125) to 1/2 (0.50) , this raises 1/2 by 25% up to 5/8 (0.625).



Yes, I agree with this interpretation. It's 25% greater than HALF that rate, not the max rate as others set up. You can say "it doesn't matter," but fundamentally the equation they set up says it is 25% greater than the max rate, which by itself makes no sense. A maximum is a maximum. Also, my understanding is that it is rare or never the case that the two statements contradict each other in a DS problem.
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Re: What is the maximum possible number of chocolate bars per hour produce [#permalink]

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New post 20 Mar 2018, 02:26
Bunuel wrote:
What is the maximum possible number of chocolate bars per hour produced by a machine?

(1) Currently, the machine produces 1,200 chocolate bars per hour.

(2) If the chocolate bar production rate is increased from half the machine's maximum rate by 300 chocolate bars per hour, the rate is increased by 25%.



X=400 is not possible as per the above solutions as it contradicts the statement A.

My Approach :
Let X be the maximum Rate
300 represents 25% of (Half the Rate)

=> \(300 = \frac{25*X}{100*2}\)

X = 2400

Option : B
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Re: What is the maximum possible number of chocolate bars per hour produce   [#permalink] 20 Mar 2018, 02:26
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