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# What is the median number of employees assigned per project

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Senior Manager
Joined: 14 Jul 2006
Posts: 281
What is the median number of employees assigned per project [#permalink]

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25 Aug 2006, 04:33
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What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.
(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.
Senior Manager
Joined: 05 Mar 2006
Posts: 348

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25 Aug 2006, 05:33
I'm sure theres some trick I'm missing.

C

S1) INSUFF
S2) INSUFF

S1&S2) Median is 3 @ 40% of the projects.
SUFF
Senior Manager
Joined: 14 Jul 2006
Posts: 281

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25 Aug 2006, 05:38
Manager
Joined: 25 Apr 2006
Posts: 50

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25 Aug 2006, 09:29
agsfaltex wrote:
I'm sure theres some trick I'm missing.

C

S1) INSUFF
S2) INSUFF

S1&S2) Median is 3 @ 40% of the projects.
SUFF

agsfaltex,

Can you please explain how you got median as 3 @ 40% of the project when combining 1 and 2.

Is it becos of the 4 or more and 2 or fewer key words...?
Senior Manager
Joined: 14 Jul 2005
Posts: 402

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25 Aug 2006, 09:41
C it is...

35% <=2 25% >=4
---------------|------------------|------------

Hence middle 40% has to be 3 (employees cannot be fractions)
Senior Manager
Joined: 05 Mar 2006
Posts: 348

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25 Aug 2006, 09:56
yessuresh wrote:
agsfaltex wrote:
I'm sure theres some trick I'm missing.

C

S1) INSUFF
S2) INSUFF

S1&S2) Median is 3 @ 40% of the projects.
SUFF

agsfaltex,

Can you please explain how you got median as 3 @ 40% of the project when combining 1 and 2.

Is it becos of the 4 or more and 2 or fewer key words...?

Its not only because the key words say thet a fraction is 4 or over and 2 or under, but because the fraction of 3 (40%) is the larger fraction of the three, making it the fraction of the whole that has the median in it.
Director
Joined: 28 Dec 2005
Posts: 752

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26 Aug 2006, 08:12
Its not only because the key words say thet a fraction is 4 or over and 2 or under, but because the fraction of 3 (40%) is the larger fraction of the three, making it the fraction of the whole that has the median in it.

Nicely put. To add to this, one must be careful to ensure that the median is actually the middle value in the case of an odd number of elements, or the average of the 2 "middle" elements in case the number is even. For example if 40% of the values are 3, 20% are 4, and 40% are 5, the median is 4, even though its not the largest fraction of the three.
26 Aug 2006, 08:12
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