parkhydel wrote:
What is the median of the nine consecutive even integers in a certain list?
(1) The median of the integers in the list is greater than 0.
(2) Of the integers in the list, the sum of the least of the negative integers and the least of the positive integers is –4.
DS11820.02
altairahmad, -8, -4, 0... will not fit in as it is an AP but not sequence of consecutive even integers.
There are 9 consecutive integers..
(1) The median of the integers in the list is greater than 0.
The nine numbers could be anything..2, 4, 6, 8, 10, 12, 14, 16, 18....Median = 10
102, 104, 106, 108, 110, 112, 114, 116, 118....Median = 110
Insufficient
(2) Of the integers in the list, the sum of the least of the negative integers and the least of the positive integers is –4.
Let the least negative integer be \(x\).
The least positive integer will be 2, if the set contains positive integers.But let us take there are NO positive integers, then \(x+0=-4.....x=-4\)
sequence would be -4, -2, 0, 2, 4, 6, 8, 10, 12 ---
But this contains positive integers too, while we took the least positive integer as none.So \(x+2=-4...x=-6\), and sequence is -6, -4, -2, 0, 2, 4, 6, 8, 10---
Median = 2.Sufficient
B