Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 12:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the probability that 2 socks chosen from 5 pairs of

Author Message
Director
Joined: 17 Oct 2005
Posts: 929
Followers: 1

Kudos [?]: 222 [0], given: 0

What is the probability that 2 socks chosen from 5 pairs of [#permalink]

### Show Tags

25 Apr 2006, 11:20
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the probability that 2 socks chosen from 5 pairs of different socks at random is exactly one pair?
Manager
Joined: 23 Jan 2006
Posts: 192
Followers: 1

Kudos [?]: 30 [0], given: 0

### Show Tags

25 Apr 2006, 11:39
2c10 = 45 possible pairs of socks

5 matching pairs.

5/45 = 1/9
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 8 [0], given: 0

### Show Tags

25 Apr 2006, 11:47
or you can also think this way 5 pairs = 10 socks

probablity of taking first one out 1 (because it can be from any pair)
probablity of taking the second one out which matches the first is 1/9

so the probablity is 1 * (1/9) = 1/9
VP
Joined: 21 Sep 2003
Posts: 1060
Location: USA
Followers: 3

Kudos [?]: 79 [0], given: 0

### Show Tags

25 Apr 2006, 12:31
ipc302 wrote:
or you can also think this way 5 pairs = 10 socks

probablity of taking first one out 1 (because it can be from any pair)
probablity of taking the second one out which matches the first is 1/9

so the probablity is 1 * (1/9) = 1/9

_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

VP
Joined: 06 Jun 2004
Posts: 1057
Location: CA
Followers: 2

Kudos [?]: 159 [0], given: 0

### Show Tags

29 Apr 2006, 00:31
ipc302 wrote:
or you can also think this way 5 pairs = 10 socks

probablity of taking first one out 1 (because it can be from any pair)
probablity of taking the second one out which matches the first is 1/9

so the probablity is 1 * (1/9) = 1/9

Late but this is how I solved it!
_________________

Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...

29 Apr 2006, 00:31
Display posts from previous: Sort by