Bunuel wrote:
What is the probability that a randomly chosen resident of Town X is female?
(1) Town X has 10,000 male residents and 15,000 female residents.
(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.
Kudos for a correct solution.
(1) Town X has 10,000 male residents and 15,000 female residents.
This statement is Super easy
\(\frac{Female}{Total (Male +Female)} = \frac{15,000}{25,000} = \frac{3}{5}\)= 60%
SUFFICIENT
(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.
\(Male = M\)
\(Female = F\)
\(1.2M=0.8F\)
\(12M=8F\)
\(M= \frac{8F}{12}\)
P(Females)= \(\frac{Female}{Female + Male}\)= \(\frac{F}{F+M}\) or\(\frac{F}{F+(8F/12)}\) =\(\frac{12F}{20F}\)= \(\frac{3}{5}= 60\)%
SUFFICIENT
ANSWER IS D
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