Bunuel wrote:

What is the range of the solutions to the equation |2x − 3| = 7?

A. 4

B. 5

C. 6

D. 7

E. 8

We'll simplify the problem stem to understand what we need to do.

This is a Precise approach.

By definition of the absolute value, the expression |2x - 3| = 7 simplifies to 2x - 3 = 7 if 2x - 3 is positive or to 3 - 2x = 7 if 2x - 3 is negative.

In the first case, we can solve for x to get x = 5.

In the second case, solving for x gives -2.

Then our range is 5 - (-2) = 7.

(D) is our answer.

Should we check x as we have to do it in inequalities? Or we have to check when we have more than 1 module? Thanks

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