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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
Hero8888 wrote:
Should we check x as we have to do it in inequalities? Or we have to check when we have more than 1 module? Thanks


Hi,

Do you mean check the result of x in the original equation?
Yes, if you have the time you can check that x = 5 and x = -2 solve the equation to make sure that you didn't make a calculation mistake.
But you don't have to.... it is partially a question of time and partially that of self-confidence: how sure are you in your result.

Does that answer your question? If not, don't hesitate to ask again.

Best of luck,
David
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
DavidTutorexamPAL wrote:
Hero8888 wrote:
Should we check x as we have to do it in inequalities? Or we have to check when we have more than 1 module? Thanks


Hi,

Do you mean check the result of x in the original equation?
Yes, if you have the time you can check that x = 5 and x = -2 solve the equation to make sure that you didn't make a calculation mistake.
But you don't have to.... it is partially a question of time and partially that of self-confidence: how sure are you in your result.

Does that answer your question? If not, don't hesitate to ask again.

Best of luck,
David


Thank you for the answer. I meant that in inequalities we check x, when we solve module problems. Should we check it in equalities or we don't have constraints?
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
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Hero8888 wrote:
DavidTutorexamPAL wrote:
Hero8888 wrote:
Should we check x as we have to do it in inequalities? Or we have to check when we have more than 1 module? Thanks


Hi,

Do you mean check the result of x in the original equation?
Yes, if you have the time you can check that x = 5 and x = -2 solve the equation to make sure that you didn't make a calculation mistake.
But you don't have to.... it is partially a question of time and partially that of self-confidence: how sure are you in your result.

Does that answer your question? If not, don't hesitate to ask again.

Best of luck,
David


Thank you for the answer. I meant that in inequalities we check x, when we solve module problems. Should we check it in equalities or we don't have constraints?


The only constraint in an equality is the 'equal' sign (and anything else that the question tells you like integers/positive/negative etc.)
So if you've found a solution and you're confident there are no calculation mistakes there is no need to check.
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
|2x - 3| = 7
|x - 3/2| = 7/2
origin = 3/2
to find range
add origin and 7/2 = 10/2= 5
and subtract 3/2-7/2 = -4/2 = -2
range = 5 - (-2) = 7
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
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Bunuel wrote:
What is the range of the solutions to the equation |2x − 3| = 7?

A. 4
B. 5
C. 6
D. 7
E. 8



|2x − 3| = 7
max => 2x-3=7, x=5
min => 2x-3=-7,x=-2
Range = max - min = 5-(-2) = 7
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
Bunuel wrote:
What is the range of the solutions to the equation |2x − 3| = 7?

A. 4
B. 5
C. 6
D. 7
E. 8


2x - 3 =7, x = 5
-2x+3 = 7, x = -2

Range = 7
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Re: What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
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Bunuel wrote:
What is the range of the solutions to the equation |2x − 3| = 7?

A. 4
B. 5
C. 6
D. 7
E. 8


Let’s first solve for when (2x - 3) is positive:

2x - 3 = 7

2x = 10

x = 5

Now let’s solve for when (2x - 3) is negative:

-(2x - 3) = 7

-2x + 3 = 7

-2x = 4

x = -2

Therefore, the range of the solutions is 5 - (-2) = 7.

Answer: D
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What is the range of the solutions to the equation |2x − 3| = 7? [#permalink]
Thanks for the explanation.
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Re: What is the range of the solutions to the equation |2x 3| = 7? [#permalink]
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Re: What is the range of the solutions to the equation |2x 3| = 7? [#permalink]
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