chetan2u wrote:
rencsee wrote:
What is the remainder obtained when \(63^{26}\) is divided by 16?
A. -2
B. -1
C. 1
D. 8
E. 10
Hi....
63 divided by 16 will leave a remainder of -1 as 64 is divisible by 16..
So 63*63*63....26times will leave a remainder of (-1)*(-1)*.....26times = \((-1)^{26}=((-1)^2)^{13}=1^{13}=1\)
C
I am not able to understand another point..
I dont see 16 repeated in the denominator.Its occuring only once.
say.. (63/16)*63^25
so first term can give say -1 as remainder later on its just 63^25 times..