Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 06:19

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the remainder of 2 to the power of k after divided

Author Message
Director
Joined: 20 Apr 2005
Posts: 584
Followers: 2

Kudos [?]: 227 [0], given: 0

What is the remainder of 2 to the power of k after divided [#permalink]

### Show Tags

28 May 2005, 14:11
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

148. What is the remainder of 2 to the power of k after divided by 10?

(1) k is divisible by 10

(2) k is divisible by 4
Director
Joined: 18 Apr 2005
Posts: 547
Location: Canuckland
Followers: 1

Kudos [?]: 37 [0], given: 0

### Show Tags

28 May 2005, 14:42
E

1) insufficient k=0 r=9, k=10 r =4, k=20 r=6
2)insufficient k=0 r=9, and then r=6 for all others k's divisible by 4

1)+2) k =0, 20, 40, 60, ... so reminder is either 9 or 6 => insufficient
Current Student
Joined: 28 Dec 2004
Posts: 3363
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 297 [0], given: 2

### Show Tags

28 May 2005, 17:21

my thinking is

I) is sufficient if we only allow positive numbers...greater than 0! but its insuff if zero is allowed...
II) should be sufficinet?
Director
Joined: 18 Apr 2005
Posts: 547
Location: Canuckland
Followers: 1

Kudos [?]: 37 [0], given: 0

### Show Tags

28 May 2005, 18:13
>I) is sufficient if we only allow positive numbers...greater than 0! but its insuff if zero is allowed...

and zero is allowed => insufficient

>II) should be sufficinet?

nope, reminders follow a repetetive pattern of 4 starting with k=4 and on, not a pattern of 10
Manager
Joined: 28 Aug 2004
Posts: 205
Followers: 1

Kudos [?]: 2 [0], given: 0

### Show Tags

28 May 2005, 22:18
I think it's D.

case of zero is out since it is not divisible by 10 (or any other number) - though theoritically, it could be.

unless of course there is a specific example from OG which says otherwise.
Intern
Joined: 30 Jan 2005
Posts: 37
Location: INDIA
Followers: 0

Kudos [?]: 5 [0], given: 0

### Show Tags

28 May 2005, 22:23
(E)

The power of 2 will be only a multiple of 2 and they do not follow any regular pattern.
say
1, 2, 4 ,8, 16, 32, 64, 126, 256, 512, 1024

Now you can see by divind by 10 you will have diffenet figures all the time in remainder so none is sufficent.
_________________

regards,

=====================
Look for the bigger Picture.

Senior Manager
Joined: 21 Mar 2004
Posts: 444
Location: Cary,NC
Followers: 3

Kudos [?]: 72 [0], given: 0

### Show Tags

29 May 2005, 09:54
Dan wrote:
I think it's D.

case of zero is out since it is not divisible by 10 (or any other number) - though theoritically, it could be.

unless of course there is a specific example from OG which says otherwise.

E it is.

0 is divisible any all real numbers.

0/x = 0
_________________

ash
________________________
I'm crossing the bridge.........

Senior Manager
Joined: 21 Mar 2004
Posts: 444
Location: Cary,NC
Followers: 3

Kudos [?]: 72 [0], given: 0

### Show Tags

29 May 2005, 09:59
To explain my answers , i forgot.

First remember that 2^4 always end in 6.

A. k =0,10,20,30

remainders = 0,4,6,4

B. k=0,4,8,12

remainders = 0,6,6,6,6,6

C. k=0,20,40,60

remainder = 0,6,6

Ans is E
_________________

ash
________________________
I'm crossing the bridge.........

29 May 2005, 09:59
Display posts from previous: Sort by

# What is the remainder of 2 to the power of k after divided

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.