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Re: What is the remainder when 10^98-1 is divided by 11 ? [#permalink]
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\(10^{98}\) - 1

Start with lower power: \(10^{2}\) - 1 = 100 - 1 = 99

=> \(\frac{99 }{ 11}\) = remainder is 0


=> \(10^{3}\) - 1 = 1000 - 1 = 999

=> \(\frac{999 }{ 11}\) = remainder is 9


=> \(10^{4}\) - 1 = 10000 - 1 = 9999

=> \(\frac{9999 }{ 11}\) = remainder is 0

Thus for the even power the remainder will be '0'.

Hence, => \(\frac{(10^{98} - 1) }{ 11}\) = remainder is 0


Answer A
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Re: What is the remainder when 10^98-1 is divided by 11 ? [#permalink]
Staphyk

Xylan

Understood now :)

Thank you. +1
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Re: What is the remainder when 10^98-1 is divided by 11 ? [#permalink]
HEY! What about this question lets us know to "Check for odd even pattern?"
How can we recognize this problem needs us to "plug in odd and even numbers" without us running out of time trying other methods?
What is our plan A, B, and C as we are reading this problem? TY




---
Thus, let's play around!
99 is divisible by 11
100 - 1 is divisible by 11
10^2 - 1 is divisible by 11 : 99=100−1=102−199=100−1=102−1 : 10-raised to even power - 1

Similarly, we can see the next big number is of the format:
9999 is divisible by 11
10000 - 1 is divisible by 11
10^4 - 1 is divisible by 11 : 9999=10000−1=104−19999=10000−1=104−1 : 10-raised to even power - 1
GMAT Club Bot
Re: What is the remainder when 10^98-1 is divided by 11 ? [#permalink]
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