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What is the sum of the digits of the positive integer n [#permalink]
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04 Nov 2010, 08:24
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What is the sum of the digits of the positive integer n where n < 99? (1) n is divisible by the square of the prime number y. (2) y^4 is a twodigit odd integer.
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Re: What is the sum of the digits of the positive integer n [#permalink]
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samark wrote: What is the sum of the digits of the positive integer n where n < 99?
(1) n is divisible by the square of the prime number y. (2) y^4 is a twodigit odd integer. Statement 1 : Square of prime number less than 99 leaves us with 3,5,7,9 (Not sufficient) Statement 2 : y^4 is a two digit odd integer (Not sufficient) But when we combine both the we are left only with y=3 and the n is divisible by 9, so we get a unique answer which also 9 Answer : C



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What is the sum of the digits of the positive integer n [#permalink]
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samark wrote: What is the sum of the digits of the positive integer n where n < 99?
1) n is divisible by the square of the prime number y.
2) y4 is a twodigit odd integer. What is the sum of the digits of the positive integer n where n < 99?(1) n is divisible by the square of the prime number y > clearly insufficient, as no info about y. 2) y^4 is a twodigit odd integer > also insufficient, as no info about n, but from this statement we know that if y is an integer then y=3 (y must be odd in order y^4 to be odd and it cannot be less than 3 or more than 3 since 1^4 and 5^4 are not two digit numbers). (1)+(2) Since from (1) y=integer then from (2) y=3, so n is divisible by 3^2=9. Number to be divisible by 9 sum of its digits must be multiple of 9, as n is twodigit number <99 then the sum of its digits must be 9 (18, 27, 36, ..., 90.). Suffiicient. Answer: C.
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Re: what is the sum.... [#permalink]
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26 Nov 2011, 06:09
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1. INSUFFICIENT e.g. take y = 2, if n = 6, 6 x 2^2 = 24, sum of digits is 6 if n = 3, 3 x 2^2 = 12, sum of digits is 3
2. INSUFFICIENT e.g. y = 3 then y^4 = 81 (a 2 digit odd number) if y = 5^1/2 then y^4=25 (a 2 digit odd number)
1. & 2. SUFFICIENT y = 3 (the only prime number with an odd two digit result when raised to the 4th power) therefore n is a multiple of 9, and the sum of the digits of all multiples of 9 is 9.



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Re: what is the sum.... [#permalink]
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26 Nov 2011, 07:27
bobfirth wrote: 1. & 2. SUFFICIENT y = 3 (the only prime number with an odd two digit result when raised to the 4th power) therefore n is a multiple of 9, and the sum of the digits of all multiples of 9 is 9. The sum of the digits of all multiples of 9 is divisible by 9. It is not generally equal to 9. For example, 99 is divisible by 9, and the sum of its digits is 18. That turns out not to affect the solution here, however, since we are only concerned with twodigit numbers less than 99, and the sum of the digits of every multiple of nine between 18 and 90 inclusive is always 9.
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Re: what is the sum.... [#permalink]
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05 Dec 2011, 11:42
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+1 C
Stmt 1 tells you that y is a small prime integer because the square has to be lower than 99 and has to have a multiple lower than 99. This leaves us 3 and 5 but we. So insuff
stmt 2 tells us that y is 3 or less but is insuff by itself because the stem of the question does not say anything about y
together y = 3 and stmt 1 tells us that it is divisible by 9 and for something to be divisible by 9 the digits add up to 9.



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Re: What is the sum of the digits of the positive integer n [#permalink]
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23 Nov 2012, 22:57
OK, so if we're going with your version... Quote: What is the sum of the digits of the positive integer n where n<99 ?
1) n is divisible by the square of y.
2) y*y*y*y (y raised to the power 4) is equal to a two digit positive odd integer. Statement 1: We don't even know that y is an integer, so the square of y could be anything... which means that n could be anything, too. (The square of y could, for example, be 1.)  incredibly insufficient Statement 2: We don't know that y is an integer, so y^4 could be any twodigit positive odd integer... and that gives us 45 possible values for y^4, most of which are not integers. And the statement says absolutely nothing about n.  still incredibly insufficient Together: y^4 could be any twodigit odd integer, which means that we have tons of possible values for y^2, including 5, 7, and 9. N could then be any multiple of 5, 7, or 9.  still not sufficient So in the version without the phrase "prime number" in statement 1, the answer would definitely be E.
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Re: What is the sum of the digits of the positive integer n [#permalink]
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23 Nov 2012, 21:24
I think your conclusion is correct, harsh6239, though I'm pretty sure that this is an MGMAT question, and I found a slightly different version of it elsewhere: What is the sum of the digits of the positive integer n where n < 99? (1) n is divisible by the square of the prime number y. (2) y^4 is a twodigit odd integer. So if we go with the version that specifies that y is prime, then... Statement 1: y could be any number of primes, which means that n must be divisible by 4, 9, 25, or 49. And that really doesn't narrow things down very much.  not sufficient Statement 2: tells us absolutely nothing about n.  not sufficient Together: since we know that y is prime, then y^4 could be 16 or 81... except that y^4 has to be odd. So y^4 must be 81. And if n < 99, then n must also be 81. The answer is C, and you were completely correct.
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Re: What is the sum of the digits of the positive integer n [#permalink]
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23 Nov 2012, 22:05
GMATNinja wrote: I think your conclusion is correct, harsh6239, though I'm pretty sure that this is an MGMAT question, and I found a slightly different version of it elsewhere: What is the sum of the digits of the positive integer n where n < 99? (1) n is divisible by the square of the prime number y. (2) y^4 is a twodigit odd integer. So if we go with the version that specifies that y is prime, then... Statement 1: y could be any number of primes, which means that n must be divisible by 4, 9, 25, or 49. And that really doesn't narrow things down very much.  not sufficient Statement 2: tells us absolutely nothing about n.  not sufficient Together: since we know that y is prime, then y^4 could be 16 or 81... except that y^4 has to be odd. So y^4 must be 81. And if n < 99, then n must also be 81. The answer is C, and you were completely correct. Thank you sir for your reply. The slightly different version of question which you have given here states that y is a prime and hence an integer. My confusion in the original question which I had posted is that if we see statement 2 then y^4 is equal to a two digit odd integer and so y need not be an integer always. so going back to statement 1 then y^2 may be a fraction and not necessarily 9. In this case answer will be E. How to confirm this one mathematically ?



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Re: what is the sum.... [#permalink]
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03 Jan 2014, 22:50
Bowtie wrote: +1 C
Stmt 1 tells you that y is a small prime integer because the square has to be lower than 99 and has to have a multiple lower than 99. This leaves us 3 and 5 but we. So insuff
stmt 2 tells us that y is 3 or less but is insuff by itself because the stem of the question does not say anything about y
together y = 3 and stmt 1 tells us that it is divisible by 9 and for something to be divisible by 9 the digits add up to 9. I think your conclusion to (1) is incomplete. y could also = 7, because (7^2)*2 = 98, which is < 99.



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Re: What is the sum of the digits of the positive integer n [#permalink]
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11 Dec 2016, 11:33
Fun Property of first ten multiples 9 > 09 18 27 36 45 54 63 72 81 90
The units digit is increasing by 1 and units digit is decreasing by 1=> Sum of digits remain the same =9
From 1 and 2 => y must be 3 Hence x must be a multiple of 9 between 0 and 99 Hence sum of its digits must be 9
Hence C
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What is the sum of the digits of the positive integer n [#permalink]
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17 Jan 2017, 23:55
What is the sum of the digits of the positive integer n where n < 99?
(1) n is divisible by the square of y. (2) y^4 is a twodigit positive odd integer.
Last edited by Vyshak on 18 Jan 2017, 00:16, edited 1 time in total.
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Re: What is the sum of the digits of the positive integer n [#permalink]
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18 Jan 2017, 06:42
Nahid078 wrote: What is the sum of the digits of the positive integer n where n < 99?
(1) n is divisible by the square of y. (2) y^4 is a twodigit positive odd integer. From Statement 1, n is divisible by square of y . y can be 1 , 4 , 9, 16 ... Clearly Insufficient . From Statement 2 , Y^4 is a two digit positive odd integer y^4 = 81 => y = 3 No information on n . So, statement is Insufficient . Combine , we know that sum of digits of n is equal to 9 . Answer is C .




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