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What is the value of –[(s + t)0] if t + s ≠ 0?

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Intern
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Joined: 16 May 2017
Posts: 41
GPA: 3.8
WE: Medicine and Health (Health Care)
What is the value of –[(s + t)0] if t + s ≠ 0?  [#permalink]

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New post 29 Sep 2018, 06:12
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  15% (low)

Question Stats:

87% (00:27) correct 13% (01:30) wrong based on 15 sessions

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What is the value of -[\((s+t)^0\)] if \(t+s\neq{0}\)?
(A) -1
(B) 0
(C) 1
(D) s+t
(E) -s+t
Senior Manager
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Posts: 267
Location: Kuwait
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Re: What is the value of –[(s + t)0] if t + s ≠ 0?  [#permalink]

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New post 29 Sep 2018, 09:45
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Important number properties to remember is that any number to the power of zero will equal 1 except for 0. Because we cannot divide by 0.

Since we are given that s+t does not equal zero

Then we know that s+t will be some number

We are given - [(s+t)^0] so - (1) = -1

Some theory on this to justify why it becomes 1

say we have x = 3 which is 3^1

If we divide 3^1/3^1 = we get 3^(1-1) = 3^0 = 1

Answer choice A

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Re: What is the value of –[(s + t)0] if t + s ≠ 0? &nbs [#permalink] 29 Sep 2018, 09:45
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What is the value of –[(s + t)0] if t + s ≠ 0?

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