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What is the value of (39^2/2^4)/(13^3/4^2)

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What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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New post 15 Jul 2019, 23:49
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

98% (00:52) correct 2% (01:38) wrong based on 45 sessions

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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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New post 16 Jul 2019, 00:06
(39^2/2^4)/(13^3/4^2)
= ((13*3)^2/2^4)/(13^3/2^(2*2))
= ((3)^2)/(13^1)=9/13

Hence E

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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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New post 16 Jul 2019, 00:12
Bunuel wrote:
What is the value of \(\frac{\frac{39^2}{2^4}}{\frac{13^3}{4^2}}\) ?

A. \(\frac{13}{2}\)

B. \(\frac{9}{2}\)

C. \(\frac{3}{2}\)

D. \(\frac{3}{13}\)

E. \(\frac{9}{13}\)


\(\frac{\frac{39^2}{2^4}}{\frac{13^3}{4^2}}\)
\(=\frac{\frac{3^2*13^2}{2^4}}{\frac{13^3}{2^4}}\)
\(=\frac{3^2*13^2}{13^3}\)
\(=\frac{3^2}{13}\)
\(=\frac{9}{13}\)

IMO E
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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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New post 16 Jul 2019, 00:38
Answer is E = 39^2 *4^2/ 2^4 * 13^3 = 13^ 2^2/ 13^3 = 9/13
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Re: What is the value of (39^2/2^4)/(13^3/4^2)   [#permalink] 16 Jul 2019, 00:38
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