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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n

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Bunuel
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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   02 Oct 2020, 03:00
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E

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What is the value of integer A ?

(1) n = nA

(2) 1^n ≠ n
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E
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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   Updated on: 02 Oct 2020, 03:55
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IMO ANSWER should be 'E'

1. n=nA
Now anything multiplied by 1 gives the same number.
If n=2, then 2=2A, that means A=1.
But if n=0, then 0=0A. We can plug in any value of A and we will still get 0.
So the value of A can be anything if n=0. Since we don't exactly know the value of n, this statement is not sufficient to find a distinct value of A.

2)1^n ≠ n
1 raised to any power always gives 1. So, 1^n should be 1.
It's given in the statement that 1^n is not equal to n. That means n ≠ 1.
But does that information help us in anyway?
I mean, A could be anything whether n is 1 or not.
So, clearly insufficient

Now using both statements:
We know n ≠ 1 and n=nA
So once again, if n=2, then 2=2A, that means A=1.
But if n=0, then 0=0A. We can plug in any value of A and we will still get 0.
Together => Insufficient

Hence E

Originally posted by lipikatiwari on 02 Oct 2020, 03:18.
Last edited by lipikatiwari on 02 Oct 2020, 03:55, edited 1 time in total.
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Re: What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   02 Oct 2020, 08:05
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Bunuel wrote:
What is the value of integer A ?

(1) n = nA

(2) 1^n ≠ n


target find value of integer A
#1
n = nA
if n = 0 then a can be 0 or any integer value hence insufficient
#2
1^n ≠ n
means that only possible of n not possible is 1 ; but relation with A is not known insufficient
from 1&2 we get n = 0,2,3, so on
so possible value of A can be any integer value when n is 0 or A can be 1 when n is any other value
insufficient
option E
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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   02 Oct 2020, 08:08
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GMATinsight
sir shouldnt the highlighted part be n ≠1 ? because at n =0 satisfies the #2 of 1^n ≠ n...


GMATinsight wrote:
Bunuel wrote:
What is the value of integer A ?

(1) n = nA

(2) 1^n ≠ n


Question: Integer A = ?

Statement 1: n = nA

i.e. nA - n = 0

i.e. n(A-1) = 0

i.e. n = 0 or A = 1

i.e. if n = 0 then A can take any value hence

NOT SUFFICIENT

STatement 2: 1^n ≠ n

i.e. n ≠ 0 but relation of n with A is unknown hence

NOT SUFFICIENT

COmbining the statements

SInce, n ≠ 0, therefore A = 1

SUFFICIENT

Answer: Option C

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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   Updated on: 03 Oct 2020, 18:17
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Bunuel wrote:
What is the value of integer A ?

(1) n = nA

(2) 1^n ≠ n


Question: Integer A = ?

Statement 1: n = nA

i.e. nA - n = 0

i.e. n(A-1) = 0

i.e. n = 0 or A = 1

i.e. if n = 0 then A can take any value hence

NOT SUFFICIENT

STatement 2: 1^n ≠ n

i.e. n = 1 but the relation of n with A is unknown hence


COmbining the statements

SInce, n = 1, therefore A can take any value hence

NOT SUFFICIENT

Answer: Option E

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Originally posted by GMATinsight on 02 Oct 2020, 03:31.
Last edited by GMATinsight on 03 Oct 2020, 18:17, edited 1 time in total.
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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink] New post   02 Oct 2020, 03:49
GMATinsight wrote:
Bunuel wrote:
What is the value of integer A ?

(1) n = nA

(2) 1^n ≠ n


Question: Integer A = ?

Statement 1: n = nA

i.e. nA - n = 0

i.e. n(A-1) = 0

i.e. n = 0 or A = 1

i.e. if n = 0 then A can take any value hence

NOT SUFFICIENT

STatement 2: 1^n ≠ n

i.e. n ≠ 0 but relation of n with A is unknown hence

NOT SUFFICIENT

COmbining the statements

SInce, n ≠ 0, therefore A = 1

SUFFICIENT

Answer: Option C

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I'm a little confused. According to you, since 1^n ≠ n, then n ≠ 0
How did you figure this out?
If n=0, then 1^0 will be 1, which is not equal to 0 (the value of n in this case). Hence, for n=0, the condition 1^n ≠ n remains true. Only for n=1, the condition 1^n ≠ n will be false. So, clearly n ≠ 1
Then how can it be concluded that n ≠ 0? Am I missing out something? 🤔
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What is the value of integer A ? (1) n = nA (2) 1^n ≠ n [#permalink]
02 Oct 2020, 03:49
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Bunuel
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