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# What is the value of {M - N} / {M^2 - N^2}? 1. {M^2 - N^2} =

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What is the value of {M - N} / {M^2 - N^2}? 1. {M^2 - N^2} = [#permalink]

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26 Oct 2009, 08:56
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Question Stats:

35% (00:49) correct 65% (00:27) wrong based on 22 sessions

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What is the value of {M - N} / {M^2 - N^2}?

1. {M^2 - N^2} = 40
2. [ M + N ] = 10

Pls explain the ans... i thought C but the OA says another .

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Re: DS question : Fractions [#permalink]

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26 Oct 2009, 09:17
kylexy wrote:
What is the value of {M - N} / {M^2 - N^2}?

1. {M^2 - N^2} = 40
2. [ M + N ] = 10

Pls explain the ans... i thought C but the OA says another .

If it were GMAT question we would most likely have that $$m\neq{n}$$ and $$m\neq{-n}$$, as if $$m=n$$ or $$m=-n$$ then the denominator becomes zero and division by zero is undefined. So not a good question.

So if we modify the question and make it GMAT type, we would have:

If $$m\neq{n}$$ and $$m\neq{-n}$$, then what is the value of $$\frac{m-n}{m^2-n^2}$$?

$$\frac{m-n}{m^2-n^2}=\frac{m-n}{(m-n)(m+n)}=\frac{1}{m+n}$$

(1) $$m^2-n^2=40$$ --> Not sufficient.
(2) $$m+n=10$$ --> $$\frac{1}{m+n}=\frac{1}{10}$$. Sufficient.

But if we take the question as it is, then the answer would be C, as we won't know for (2) whether the answer is 1/10 or undefined in case $$m=n$$.
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Re: DS question : Fractions [#permalink]

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26 Oct 2009, 09:20

since (m-n)/m^2-n^2 = 1/(m+n), we only need m+n.
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Re: DS question : Fractions [#permalink]

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26 Oct 2009, 10:34
Surely B....
M-N/(M+N)(M-N)=1/M+N=1/10

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Re: DS question : Fractions [#permalink]

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26 Oct 2009, 22:08
Hunt wrote:
Surely B....
M-N/(M+N)(M-N)=1/M+N=1/10

Answer is E...i don understand either!!
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Re: DS question : Fractions [#permalink]

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27 Oct 2009, 10:54
the above expr can be written as 1/(m+n) & the value of (m+n) is given by statement 2.

I will choose option B

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Re: DS question : Fractions [#permalink]

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27 Oct 2009, 11:54
kylexy.. it surely can not be E... whats the source......

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Re: DS question : Fractions [#permalink]

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27 Oct 2009, 12:36
Hunt wrote:
kylexy.. it surely can not be E... whats the source......

its one of the "toughies" from PR
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27 Sep 2010, 03:13
What is the value of (m-n)/(m*2-n*2) = ?

1.) m*2-n*2 = 40
2.) m+n = 10

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27 Sep 2010, 03:27
sahilkhurana06 wrote:
What is the value of (m-n)/(m*2-n*2) = ?

1.) m*2-n*2 = 40
2.) m+n = 10

Moved to DS forum

I take it by m*2-n*2 you mean m^2-n^2 ?

Note that (m-n)/(m^2-n^2) = 1/(m+n) as long as m-n is not equal to 0

1) Not sufficient, as we dont know m+n
2) Would have been sufficient if we knew m-n is not 0.

1+2) Sufficient, as we know m+n and we also know m-n is not zero, as m^2-n^2=(m+n)(m-n)

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27 Sep 2010, 03:35
Yes..there was some confusion..Actually the answer is C only..Thanks for giving your precious time..

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Re: DS question : Fractions [#permalink]

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27 Sep 2010, 08:39
What's the final answer, B or C
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Re: DS question : Fractions [#permalink]

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28 Sep 2010, 14:37

m^2-n^2=(m+n)(m-n) thus, (m-n)/(m+n)(m-n) equals 1/m+n

since we are given that m+n=10 we have sufficient information to answer this question with (2) alone.

B

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Re: DS question : Fractions [#permalink]

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28 Sep 2010, 14:55
Bruno2000 wrote:

m^2-n^2=(m+n)(m-n) thus, (m-n)/(m+n)(m-n) equals 1/m+n

since we are given that m+n=10 we have sufficient information to answer this question with (2) alone.

B

Nope. (check shrouded's explanation).

(M-N)/(M^2-N^2) = 1/(M+N) only possible if M =/ N or M=/ -N

1. {M^2 - N^2} = 40 => M =/ N
2. [ M + N ] = 10 => M =/ -N

Therefore, we need both. Hence, C
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Re: DS question : Fractions [#permalink]

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06 Jan 2011, 09:39
I agree on B

Posted from GMAT ToolKit

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Re: DS question : Fractions   [#permalink] 06 Jan 2011, 09:39
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