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# What is the value of x? 1) x^x = 2x 2) = x^2

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What is the value of x? 1) x^x = 2x 2) = x^2 [#permalink]

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05 Feb 2004, 18:54
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What is the value of x?

1) x^x = 2x
2) [x] = x^2
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shubhangi

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05 Feb 2004, 19:34
From 1) if 0^0 = 0 then possible answers can be 0 and 2
From 2) we get 0, -1, 1
Therefore C, if 0^0=0
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Paul

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05 Feb 2004, 19:43
0^0 is undefined.

I believe A is the answer.

X^X = 2 * X so X = 2
[X] = X^2 X = 0, -1, 1

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05 Feb 2004, 19:46
oops, I meant otherwise A is the answer since only 2 can result from first stem. How silly
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Paul

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05 Feb 2004, 20:51
Quote:
[X] = X^2 X = 0, -1, 1

[-1] = -1

Last edited by Zhung Gazi on 05 Feb 2004, 21:11, edited 3 times in total.

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05 Feb 2004, 20:59
What are you trying to demonstrate here Zhung Gazi?

Quote:
[-1] = -1

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Paul

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05 Feb 2004, 21:06
Paul wrote:
What are you trying to demonstrate here Zhung Gazi?

Quote:
[-1] = -1

[X] = X^2
[-1] = -1 != (-1)^2

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05 Feb 2004, 23:02
Zhung Gazi..u have an eagle's eye. You caught paul and Anand correcty.

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05 Feb 2004, 23:29
When did the absolute value of -1 = -1 ?
Absolute value is always +ve

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05 Feb 2004, 23:57
[x] = integral part of x
{x} = x - [x] = fractional part of x
|x| = absolute value of x

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06 Feb 2004, 05:21
Well, this got me totally confused. shubhangi, can you confirm what you meant by [x]? Ever since "[]" was used on this board, it always stood for abs. value. Besides, GMAT never really tested you on the "integral" or "fractional" part of any number
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06 Feb 2004, 09:37
I beleive the answer should be A

1. x^2 = 2x which means x = 2 sufficient
2. x^2 = x X could be = or 1. Insufficient

How can we assume [x] to be an integral part of x. It is not explicitly stated in the question

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06 Feb 2004, 09:37
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