Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 27 May 2017, 12:35

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is x? A. X is three times the sum of its digits B. X is

Author Message
Manager
Joined: 09 Feb 2003
Posts: 82
Followers: 1

Kudos [?]: 0 [0], given: 0

What is x? A. X is three times the sum of its digits B. X is [#permalink]

### Show Tags

18 Nov 2003, 11:28
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is x?
A. X is three times the sum of its digits
B. X is a two digit number
ShouldnтАЩt it be C?
Senior Manager
Joined: 30 Aug 2003
Posts: 322
Location: dallas , tx
Followers: 1

Kudos [?]: 27 [0], given: 0

### Show Tags

18 Nov 2003, 11:39
I guess the asnwer should be E
coz it can be any number.. X= 1+1*3
and for choice B it can be any 2 digit number..2+3=5*3=15
_________________

shubhangi

Manager
Joined: 09 Feb 2003
Posts: 82
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

18 Nov 2003, 11:49
Not sure, but this is how I solve it:
X=ab ( a=tens, b=ones)
(10*a )+ b=3 (a+b)
a=7/2 b, if x is two digit, b should be 2 to make a less than 10, therefore b=2 and a=7
x= 72
Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States
Followers: 1

Kudos [?]: 13 [0], given: 0

### Show Tags

18 Nov 2003, 11:55
sarnia wrote:
Not sure, but this is how I solve it:
X=ab ( a=tens, b=ones)
(10*a )+ b=3 (a+b)
a=7/2 b, if x is two digit, b should be 2 to make a less than 10, therefore b=2 and a=7
x= 72

Correction:
a = 2/7b

I think now you'll see that Statement (2) doesn't do anything for us.
Manager
Joined: 09 Feb 2003
Posts: 82
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

18 Nov 2003, 12:08
My mistake, a=2/7 b but shouldnтАЩt тАЬbтАЭ be 7 for a to be less than 10
Thanks
Director
Joined: 13 Nov 2003
Posts: 961
Location: Florida
Followers: 1

Kudos [?]: 145 [0], given: 0

### Show Tags

18 Nov 2003, 12:29
you are right, sarnia. b will be 7 and a will be 2, thus 27.
Manager
Joined: 11 Oct 2003
Posts: 102
Location: USA
Followers: 1

Kudos [?]: 0 [0], given: 0

It is A and not C [#permalink]

### Show Tags

18 Nov 2003, 12:53
Please try doing the same for a 3 digit number. You will see that it is not possible to have A, B and C all single digit to form 100A+10B+C.
Manager
Joined: 26 Aug 2003
Posts: 233
Location: United States
Followers: 1

Kudos [?]: 13 [0], given: 0

### Show Tags

18 Nov 2003, 13:05
sarnia wrote:
My mistake, a=2/7 b but shouldnтАЩt тАЬbтАЭ be 7 for a to be less than 10
Thanks

I think Statement (1) is sufficient because 27 is the only such integer. I tried to find solution for 3 and 4 digit numbers before posting and wasn't able to come up with anything. In fact, I would hit dead end after two iterations.

IMO, this is a really bad question. Whoever generated it. One must know something so whacky as this to solve the problem. But I give props to sarnia for taking the right approach in solving it.
Intern
Joined: 30 Oct 2003
Posts: 33
Location: uk
Followers: 0

Kudos [?]: 3 [0], given: 0

### Show Tags

19 Nov 2003, 18:25
I think it is a very good question.

Consider 3 cases

Case 1: X cannot be a in single digits. Obviously.
Case 2: Say x has 2 digits, then 10a+b=3(a+b)=>a/b=2/7. Since a and b have to be single digits and not equal to 0, the only option is a=2,b=7.
Case 3: Say x has 3 digits, the maximum value can be 999, sum of digits = 27. Multiply with 3 to get 81. Even the maximum of the sum will not get near the minimum of 3 digit number 100. Therefore X cannot be a 3 digit number.

The logic in Case 3 can be extended for numbers with more than 2 digits (4,5 etc.). Therefore the answer is A.
19 Nov 2003, 18:25
Display posts from previous: Sort by