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what must be added to x/y to make 2y/x ?

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what must be added to x/y to make 2y/x ?  [#permalink]

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New post 24 Feb 2019, 02:26
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A
B
C
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Question Stats:

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what must be added to x/y to make 2y/x ?

A)\(\frac{2x^2}{y}\)
B)\(\frac{(xy - y^2)}{x}\)
C)\(\frac{(2y^2 - x^2)}{xy}\)
D)\(\frac{x}{y}\)
E)\(\frac{x}{y^2}\)
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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 25 Feb 2019, 05:53
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It's not often that I see addition questions – it made me think.
What is the source?
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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 24 Feb 2019, 02:37
Using Test It:
Let’s say X=2 and Y=3, équation becomes
2/3 + A = 6/2
A = 7/3

Let’s plug X and Y into the answers and see which one gives us 7/3

A) 8/3
B) negative, I stop
C) 14/6 ... 7/3, good answer
Rapid check for D and E to be sure but those are clearly wrong

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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 24 Feb 2019, 03:01
Let what must be added =?
Now
? + x/y = 2y/x
? = 2y/x - x/y
? =(y/y)2y/x - (x/x)x/y
? = 2y^2/xy - x^2/xy
? = (2y^2 - x^2)/xy
Ans is C
Hope it helps

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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 25 Feb 2019, 06:23
Isn’t it based on your level of Quant questions that’s why you might not see a simple question like this one ?
philipssonicare wrote:
It's not often that I see addition questions – it made me think.
What is the source?


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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 25 Feb 2019, 13:38
Staphyk I feel I see lots of question applying quadratic rules and exponent rules, division and multiplication. I've been doing sub-600 level questions recently for lazy practice, so they can't get any easier!
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Re: what must be added to x/y to make 2y/x ?  [#permalink]

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New post 27 Feb 2019, 10:19
selim wrote:
what must be added to x/y to make 2y/x ?

A)\(\frac{2x^2}{y}\)
B)\(\frac{(xy - y^2)}{x}\)
C)\(\frac{(2y^2 - x^2)}{xy}\)
D)\(\frac{x}{y}\)
E)\(\frac{x}{y^2}\)


We can let k = the number that must be added and create the equation:

x/y + k = 2y/x

k = 2y/x - x/y

Getting a common denominator of xy, we have:

k = 2y^2/(xy) - x^2/(xy)

k = (2y^2 - x^2)/(xy)

Answer: C
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Re: what must be added to x/y to make 2y/x ?   [#permalink] 27 Feb 2019, 10:19
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