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What is the sum of the remainders of 6 consecutive intege

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What is the sum of the remainders of 6 consecutive intege  [#permalink]

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New post 24 Mar 2018, 23:27
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A
B
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D
E

Difficulty:

  15% (low)

Question Stats:

86% (00:31) correct 14% (01:39) wrong based on 49 sessions

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What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

1. 0
2. 1
3. 10
4. 15
5. 16

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Re: What is the sum of the remainders of 6 consecutive intege  [#permalink]

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New post 24 Mar 2018, 23:42
Consecutive integers taken 1,2,3,4,5,6
Remainder of 1/6 = 1
Remainder of 2/6 = 2
Similarly
remainders are 1,2,3,4,5,0

Sum =1+2+3+4+5+0 =15

Hence D

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Re: What is the sum of the remainders of 6 consecutive intege  [#permalink]

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New post 25 Mar 2018, 00:20
QZ wrote:
What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

1. 0
2. 1
3. 10
4. 15
5. 16


Algebraically, we can solve the question as -

Let the 6 consecutive numbers be 6k+1, 6k+2, 6k+3, 6k+4, 6k+5 and 6k+6. Hence when these numbers are divided by 6, remainder will be

1, 2, 3, 4, 5, 0 and Sum of remainder will be =1+2+3+4+5+0=15

Option D
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Re: What is the sum of the remainders of 6 consecutive intege  [#permalink]

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New post 08 Apr 2018, 07:07
1
Consecutive integers taken 1,2,3,4,5,6
Remainder of 1/6 = 1
Remainder of 2/6 = 2
Similarly
remainders are 1,2,3,4,5,0

Sum =1+2+3+4+5+0 =15

Hence D
Re: What is the sum of the remainders of 6 consecutive intege &nbs [#permalink] 08 Apr 2018, 07:07
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