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What was the average (arithmetic mean) of the scores of the five stude

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Math Expert

Joined: 02 Sep 2009

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What was the average (arithmetic mean) of the scores of the five stude [#permalink]

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12 Dec 2017, 10:18

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Difficulty:

5% (low)

Question Stats:

91% (01:05) correct

9% (01:00) wrong

based on 66 sessions

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What was the average (arithmetic mean) of the scores of the five students in Test 2?

(A) 60
(B) 65
(C) 68
(D) 70
(E) 72

Spoiler: OA

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Re: What was the average (arithmetic mean) of the scores of the five stude [#permalink]

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12 Dec 2017, 13:50

From the image, we get the scores in Test 2 for all the students

Student A,C - 70
Student B,E - 60
Student D - 80

Therefore, Average of scores in Test 2 is $\frac{70*2 + 60*2 + 80}{5} = \frac{140 + 200}{5} = \frac{340}{5} = 68$(Option C)
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Re: What was the average (arithmetic mean) of the scores of the five stude [#permalink]

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13 Aug 2018, 10:08

Bunuel wrote:

What was the average (arithmetic mean) of the scores of the five students in Test 2?

(A) 60
(B) 65
(C) 68
(D) 70
(E) 72

Dear Moderator,
While going through the coordinate geometry forum found this question. This seems more like a graphs and illustrations problem.Hope you will look into this. Thank you.
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Re: What was the average (arithmetic mean) of the scores of the five stude [#permalink]

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13 Aug 2018, 10:43

Bunuel wrote:

What was the average (arithmetic mean) of the scores of the five students in Test 2?

(A) 60
(B) 65
(C) 68
(D) 70
(E) 72

$\frac{70+60+70+80+60}{5}$

$= 68$, Answer must be (C)
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Re: What was the average (arithmetic mean) of the scores of the five stude [#permalink]

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18 Aug 2018, 19:26

Bunuel wrote:

What was the average (arithmetic mean) of the scores of the five students in Test 2?

(A) 60
(B) 65
(C) 68
(D) 70
(E) 72

The average of the 5 students is:

(70 + 60 + 70 + 80 + 60)/5 = 340/5 = 68

Alternate Solution:

Note that if Student E were not included, the average of B and D would be 70, and thus the entire test average would be exactly 70. Since Student E has a score of 60 in Test 2, the overall average of all 5 students is just less than 70, so 68 is the logical (and correct) answer.

Answer: C
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