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When 15n is divided by 6, the remainder is x. What is value [#permalink]
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06 Oct 2009, 02:06
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When 15n is divided by 6, the remainder is x. What is value of x?
1/ When n is devided by 2, the remainder is 0 2/ When n is divided by 3, the remainder is 0



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Re: Divisibility/ Remainders [#permalink]
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06 Oct 2009, 03:34
1/ When n is divided by 2, the remainder is 0 This means n is even. 15x2 = 30. 15n will always be divisible by 30. You can test this by using n=4,6,8 etc. 30/6 has remainder 0. Sufficient.
2/ When n is divided by 3, the remainder is 0 n = 3,6,9... n=3 15n=45 45/6 has remainder 3 n=6 15n=90 90/6 has remainder 0 Not sufficient.
ANS = A.



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Re: Divisibility/ Remainders [#permalink]
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07 Oct 2009, 13:55
Here is another solution.
When 15n is divided by 6, the remainder is x. Simplyfing the equation 15 * / 6 results in 5n/2 and also states that x is the remainder.
When a number is divided by 2, the reaminder can be 0 thru n1 which means in our case x can be either 0 or 1. Now the question is to find the value or X. In 5n/2, 5 is not divisible by 2. So the value of x depends on whether n is even(in which case x = 0) or n is odd(in which case x = 1).
Clue 1 When n is divided by 2, remainder is 0. Clearly n is even and hence x is zero. Sufficient. Clue 2 When n is divided by 3, remainder is 0. Here n can be odd(for ex  9) or even(for ex  6) So x can be 1 or 1. Not sufficient.
Ans = A




Re: Divisibility/ Remainders
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07 Oct 2009, 13:55






