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When a player in a certain game tossed a coin a number of ti [#permalink]

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When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result?

(1) The player tossed the coin 24 times. (2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result? 1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

x= tails x+4= heads.

1:2x+4=24 --> 2x=20 --> x=10 so he tossed the heads x+4--> 14 times.

2: we are given another ratio but this doesnt change anything.

x + 3(x+4)=52 --> 4x+12=52 --> 4x=40 --> x=10 again 14 times is the answer.

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result? 1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result? 1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

Soln: 1) The player tossed the coin 24 times Total number of heads = H Total number of tails = T H + T = 24 H - T = 4 Solving both equations we get H = 14 Statement 1 alone is sufficient.

2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points. Total number of heads = H Total number of tails = T 3H + T = 52 H - T = 4 Solving these two equations we get H = 14 Statement 2 alone is sufficient.

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result? 1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

let total of tosses be n no of tails T no of Heads H = T + 4 Also n = H + T = 2T + 4

S1: n = 24... Therefore SUFF.... as 24 = 2T + 4 gives T = 10...& H = 14

S2: 3H + T = 52 ... 3T + 12 + T = 52 ...gives T = 10 & H = 14. SUFF...

D..
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1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

given for certain number of times 4 more heads than tails

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result? 1) The player tossed the coin 24 times 2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points.

x - Number of tails x+4 - Number of heads

1) x+x+4 = 24 can solve for x. Sufficient 2) 3(x+4) + x = 52 can solve for x. Sufficient

Hence D.

Is this really a 700 - plus questions as mentioned by the tag???

When a player in a certain game tossed a coin a number of times, 4 more heads than tails resulted. Heads or tails resulted each time the player tossed the coin. How many times did heads result?

Given: H-4=T. Question: T=?

(1) The player tossed the coin 24 times. H+(H-4)=24. We can find H. Sufficient.

(2) The player received 3 points each time heads resulted and 1 point each time tails resulted, for a total of 52 points. 3H+1*(H-4)=52. The same here: we can find H. Sufficient.