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When a truck travels at 60 miles per hour, it uses 30% more

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When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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Updated on: 20 Aug 2013, 06:24
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When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?

A. 160 minutes
B. 180 minutes
C. 190 minutes
D. 192 minutes
E. 195 minutes

Originally posted by faifai0714 on 18 Sep 2006, 15:15.
Last edited by Bunuel on 20 Aug 2013, 06:24, edited 1 time in total.
Edited the question and added the OA.
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18 Sep 2006, 15:24
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B. 180 minutes

E50 = 20mpg
E60 = 0.7 x E50 = 14mpg

Amount of gas = 10 gallons
Dist to dest = 160 miles
Speed = 60 mph

Total time to dest = 160/60 x 60 = 160 minutes

As 10 x 14 < 160, need to stop 20 minutes to refuel.

Total time = 160 + 20 = 180 minutes.
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Re: Word problem - time  [#permalink]

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27 Feb 2011, 12:09
3
Sol:
The question is how many times the truck stops for refueling?

If it didn't have to stop; then the truck would travel a distance of 160 m @ 60mph in

160/60 = 2hours 40minutes

Let's see how many times the truck will have to stop for the gas;

@ 60 mph, the mileage of the truck will be;
$$\frac{20}{1.3}$$

So; in 10 gallons; the truck will travel
$$\frac{20*10}{1.3} miles$$
$$\frac{20*10}{1.3} miles \approx 153 miles$$

Still few miles short of 160. Thus; refueling the tank once would suffice even if the tank's capacity is just 10 gallons.

If the truck stopped once for the fill; then it spent an extra 20 minutes.

Total travel time = 2 hour 40 min+20 min = 3 hours = 180 mins

Ans: "B"
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Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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20 Aug 2013, 06:34
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prasannajeet wrote:
When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?

A. 160 minutes
B. 180 minutes
C. 190 minutes
D. 192 minutes
E. 195 minutes

Hi Bunuel

Can u clarify, is gallon consumption has to play a vital part to solve it???
I don't think so. Its mentioned to make someone confused...

Rgds
Prasannajeet

We use consumption to see whether 10 gallons are enough to travel 160 miles, so whether 20 additional minutes will be needed to refuel while covering the distance.

Hope it helps.
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Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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20 Aug 2013, 07:38
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faifai0714 wrote:
When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?

A. 160 minutes
B. 180 minutes
C. 190 minutes
D. 192 minutes
E. 195 minutes

The answer is indeed B, but I feel like this question could be made more interesting (or perhaps just harder) if we introduced a choice. The driver can drive at 50 mph or 60 mph. What is the minimum amount of time he could take to reach his destination. Then we'd need to add in 160 miles / 50 mph = 3.2 hours, or 180 minutes + ($$\frac{1}{5} * 60$$) = 192 minutes (not coincidentally answer choice D).

Then we could compare D to B and determine that going 60 mph is faster than 50 and pick B as the overall answer. Of course this might make people think that if he drove at ~55 mph he'd probably get there in under 3 hours without having to refuel.

Just fuel for understanding GMAT algebra concepts!

Thanks!
-Ron
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18 Sep 2006, 15:41
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at 50 miles/hr rate,
every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr}
160/50=3.2hr
3.2*2.5=8 gallons
at 60 miles/hr rate, the truck use 30% more gasline
8*1.3=10.4 gallons
total time=160/60*60+20=180minutes
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19 Sep 2006, 10:49
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@60 mph mileage = (1 - 0.3) * 20 = 14 mpg

Time = Distance/speed
TIme = 160/60 hours
Time = 160/60 * 60 minutes
Time = 160 minutes.
Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,

Time = 160 + 20 = 180.

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Updated on: 25 Sep 2008, 00:59
1
Iawfy wrote:

at 50 miles/hr rate,
every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr}
160/50=3.2hr
3.2*2.5=8 gallons
at 60 miles/hr rate, the truck use 30% more gasline
8*1.3=10.4 gallons
total time=160/60*60+20=180minutes

Hi iamwfy,

we can conclude the above thing fast.......

At 50mph truck needs 1 gallon for 20 miles.
At 60mph truck needs 1.3gallons for the same 20 miles(bcoz the consumption is 30%higher)

It has to travel 160 miles at 60mph,so it will need 1.3 x 8 =10.4 gallons.
Since it has only 10 gallons it has to wait for 20 minutes to get the extra 0.4 gallon.

So total time is 160minutes +20 minutes = 180
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Originally posted by cicerone on 19 Sep 2006, 01:30.
Last edited by cicerone on 25 Sep 2008, 00:59, edited 1 time in total.
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19 Sep 2006, 10:50
lan583 wrote:
cicerone wrote:
Iawfy wrote:

at 50 miles/hr rate,
every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr}
160/50=3.2hr
3.2*2.5=8 gallons
at 60 miles/hr rate, the truck use 30% more gasline
8*1.3=10.4 gallons
total time=160/60*60+20=180minutes

Hi iamwfy,

we can conclude the above thing fast.......

At 50mph truck needs 1 gallon for 20 miles.
At 60mph truck needs 1.3gallons for the same 20 miles(bcoz the consumption is 30%higher)

It has to travel 160 miles at 60mph,so it will need 1.3 x 8 =10.4 gallons.
Since it has only 10 gallons it has to wait for 20 minutes to get the extra 0.4 gallon.

So total time is 160minutes +20 minutes = 180

Where did you get 160 minutes? Thanks

To travel 160 miles with 60mph it will obviously take 160 minutes and 20 more minutes to fill the extra gas needed
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Re: Word problem - time  [#permalink]

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Updated on: 27 Feb 2011, 12:11
New mileage @ 60mph = 20/1.3 miles per gallon
Gallons of gas required to cover 160 miles @ 60mph = 160 / (20 / 1.3). But its tank hold only 10 gallons. Hence the truck will make one stop for 20 min.

Normal time to cover 160 miles = 160/60 hr = 160 mins.
Now total time = 160 mins + 20 mins = 180 mins

When a truck travels at 60 mph, it takes 30% more gasoline to travel any distance than it does when it travels at 50 mph. The truck can travel 20 miles on a gallon of gas if it is travelling at 50mph. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 mph?

A/ 160 min
B/ 180 min
C/ 190 min
D/ 192 min
E/ 195 min

Originally posted by gmat1220 on 27 Feb 2011, 12:04.
Last edited by gmat1220 on 27 Feb 2011, 12:11, edited 1 time in total.
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Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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20 Aug 2013, 06:17
Hi Bunuel

Can u clarify, is gallon consumption has to play a vital part to solve it???
I don't think so. Its mentioned to make someone confused...

Rgds
Prasannajeet
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Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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20 Aug 2013, 07:15
Hi Bunuel

Understood and thanx for explanation

Rgds
Prasannajeet
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Posts: 60646
Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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20 Aug 2013, 07:48
VeritasPrepRon wrote:
faifai0714 wrote:
When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?

A. 160 minutes
B. 180 minutes
C. 190 minutes
D. 192 minutes
E. 195 minutes

The answer is indeed B, but I feel like this question could be made more interesting (or perhaps just harder) if we introduced a choice. The driver can drive at 50 mph or 60 mph. What is the minimum amount of time he could take to reach his destination. Then we'd need to add in 160 miles / 50 mph = 3.2 hours, or 180 minutes + ($$\frac{1}{5} * 60$$) = 192 minutes (not coincidentally answer choice D).

Then we could compare D to B and determine that going 60 mph is faster than 50 and pick B as the overall answer. Of course this might make people think that if he drove at ~55 mph he'd probably get there in under 3 hours without having to refuel.

Just fuel for understanding GMAT algebra concepts!

Thanks!
-Ron

+1.

Thank you Ron for giving me an idea for a question.
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Re: When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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26 Jun 2018, 06:04
asaf wrote:
@60 mph mileage = (1 - 0.3) * 20 = 14 mpg

Time = Distance/speed
TIme = 160/60 hours
Time = 160/60 * 60 minutes
Time = 160 minutes.
Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,

Time = 160 + 20 = 180.

The consumption of fuel depends on time or distance, on which one? Please make me clear.
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When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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26 Jun 2018, 09:31
Naren7 wrote:
asaf wrote:
@60 mph mileage = (1 - 0.3) * 20 = 14 mpg

Time = Distance/speed
TIme = 160/60 hours
Time = 160/60 * 60 minutes
Time = 160 minutes.
Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,

Time = 160 + 20 = 180.

The consumption of fuel depends on time or distance, on which one? Please make me clear.

Yes exactly.
I also thought different from everyone.
If travelling at 50 miles/hr - 20 miles/gallon
If travelling at 60 miles/hr (30% more fuel consumption that means 50miles/hr will have 30% more distance) = 20x(10/13).
So it should be made clear in the question.
And then solution becomes critical and answer comes 204 minutes.
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When a truck travels at 60 miles per hour, it uses 30% more  [#permalink]

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04 Mar 2019, 06:20
Given: 50 mi/hr, gas = 20 mi/hr, 10 gal of gas

1) At 60 mi/hr gas consumption increases by 30% --> (7/10)*20 mi/gal = 14 mi/gal

2) d = 160 mi, so in 10 gals we get 140 mi (this part takes 7/3 hrs) --> 20 mi left

3) then refuel for 20 min, +1/3 hr

4) We still have to cover 20 miles, so 20mi/60 mi/hr = +1/3 hr

5) 7/3 + 1/3 + 1/3 = 9/3 = 3 hours*60 min/1 hr = 180 minutes

Is this a realistic 700 level rates question? The problem is not hard to do but the amount of information makes it time consuming.
When a truck travels at 60 miles per hour, it uses 30% more   [#permalink] 04 Mar 2019, 06:20
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