Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 02 Sep 2006
Posts: 215

When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
Updated on: 20 Aug 2013, 06:24
Question Stats:
72% (03:06) correct 28% (03:23) wrong based on 271 sessions
HideShow timer Statistics
When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour? A. 160 minutes B. 180 minutes C. 190 minutes D. 192 minutes E. 195 minutes
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by faifai0714 on 18 Sep 2006, 15:15.
Last edited by Bunuel on 20 Aug 2013, 06:24, edited 1 time in total.
Edited the question and added the OA.



Director
Joined: 02 Jun 2006
Posts: 955

B. 180 minutes
E50 = 20mpg
E60 = 0.7 x E50 = 14mpg
Amount of gas = 10 gallons
Dist to dest = 160 miles
Speed = 60 mph
Total time to dest = 160/60 x 60 = 160 minutes
As 10 x 14 < 160, need to stop 20 minutes to refuel.
Total time = 160 + 20 = 180 minutes.



Retired Moderator
Joined: 20 Dec 2010
Posts: 1557

Re: Word problem  time
[#permalink]
Show Tags
27 Feb 2011, 12:09
Sol: The question is how many times the truck stops for refueling? If it didn't have to stop; then the truck would travel a distance of 160 m @ 60mph in 160/60 = 2hours 40minutes Let's see how many times the truck will have to stop for the gas; @ 60 mph, the mileage of the truck will be; \(\frac{20}{1.3}\) So; in 10 gallons; the truck will travel \(\frac{20*10}{1.3} miles\) \(\frac{20*10}{1.3} miles \approx 153 miles\) Still few miles short of 160. Thus; refueling the tank once would suffice even if the tank's capacity is just 10 gallons. If the truck stopped once for the fill; then it spent an extra 20 minutes. Total travel time = 2 hour 40 min+20 min = 3 hours = 180 mins Ans: "B"
_________________



Math Expert
Joined: 02 Sep 2009
Posts: 59268

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
20 Aug 2013, 06:34
prasannajeet wrote: When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?
A. 160 minutes B. 180 minutes C. 190 minutes D. 192 minutes E. 195 minutes
Hi Bunuel
Can u clarify, is gallon consumption has to play a vital part to solve it??? I don't think so. Its mentioned to make someone confused...
Rgds Prasannajeet We use consumption to see whether 10 gallons are enough to travel 160 miles, so whether 20 additional minutes will be needed to refuel while covering the distance. Hope it helps.
_________________



Veritas Prep GMAT Instructor
Joined: 11 Dec 2012
Posts: 312

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
20 Aug 2013, 07:38
faifai0714 wrote: When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?
A. 160 minutes B. 180 minutes C. 190 minutes D. 192 minutes E. 195 minutes The answer is indeed B, but I feel like this question could be made more interesting (or perhaps just harder) if we introduced a choice. The driver can drive at 50 mph or 60 mph. What is the minimum amount of time he could take to reach his destination. Then we'd need to add in 160 miles / 50 mph = 3.2 hours, or 180 minutes + (\(\frac{1}{5} * 60\)) = 192 minutes (not coincidentally answer choice D). Then we could compare D to B and determine that going 60 mph is faster than 50 and pick B as the overall answer. Of course this might make people think that if he drove at ~55 mph he'd probably get there in under 3 hours without having to refuel. Just fuel for understanding GMAT algebra concepts! Thanks! Ron
_________________



Intern
Joined: 17 Sep 2006
Posts: 29
Location: China

the answer is B
at 50 miles/hr rate,
every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr}
160/50=3.2hr
3.2*2.5=8 gallons
at 60 miles/hr rate, the truck use 30% more gasline
8*1.3=10.4 gallons
total time=160/60*60+20=180minutes



Senior Manager
Joined: 06 Sep 2006
Posts: 450

@60 mph mileage = (1  0.3) * 20 = 14 mpg
Time = Distance/speed
TIme = 160/60 hours
Time = 160/60 * 60 minutes
Time = 160 minutes.
Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,
Time = 160 + 20 = 180.
ANSWER: B



Manager
Joined: 28 Aug 2006
Posts: 244

[#permalink]
Show Tags
Updated on: 25 Sep 2008, 00:59
Iawfy wrote: the answer is B
at 50 miles/hr rate, every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr} 160/50=3.2hr 3.2*2.5=8 gallons at 60 miles/hr rate, the truck use 30% more gasline 8*1.3=10.4 gallons total time=160/60*60+20=180minutes Hi iamwfy, we can conclude the above thing fast....... At 50mph truck needs 1 gallon for 20 miles. At 60mph truck needs 1.3gallons for the same 20 miles(bcoz the consumption is 30%higher) It has to travel 160 miles at 60mph,so it will need 1.3 x 8 =10.4 gallons. Since it has only 10 gallons it has to wait for 20 minutes to get the extra 0.4 gallon. So total time is 160minutes +20 minutes = 180
_________________
Originally posted by cicerone on 19 Sep 2006, 01:30.
Last edited by cicerone on 25 Sep 2008, 00:59, edited 1 time in total.



Manager
Joined: 28 Aug 2006
Posts: 244

lan583 wrote: cicerone wrote: Iawfy wrote: the answer is B
at 50 miles/hr rate, every hr needs 2.5gallons of gas {(50 miles/hr)/(20miles/ Gallon)=2.5 gollons/hr} 160/50=3.2hr 3.2*2.5=8 gallons at 60 miles/hr rate, the truck use 30% more gasline 8*1.3=10.4 gallons total time=160/60*60+20=180minutes Hi iamwfy, we can conclude the above thing fast....... At 50mph truck needs 1 gallon for 20 miles. At 60mph truck needs 1.3gallons for the same 20 miles(bcoz the consumption is 30%higher) It has to travel 160 miles at 60mph,so it will need 1.3 x 8 =10.4 gallons. Since it has only 10 gallons it has to wait for 20 minutes to get the extra 0.4 gallon. So total time is 160minutes +20 minutes = 180 Where did you get 160 minutes? Thanks
To travel 160 miles with 60mph it will obviously take 160 minutes and 20 more minutes to fill the extra gas needed



Director
Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
Posts: 647

Re: Word problem  time
[#permalink]
Show Tags
Updated on: 27 Feb 2011, 12:11
New mileage @ 60mph = 20/1.3 miles per gallon Gallons of gas required to cover 160 miles @ 60mph = 160 / (20 / 1.3). But its tank hold only 10 gallons. Hence the truck will make one stop for 20 min. Normal time to cover 160 miles = 160/60 hr = 160 mins. Now total time = 160 mins + 20 mins = 180 mins Madelaine88 wrote: When a truck travels at 60 mph, it takes 30% more gasoline to travel any distance than it does when it travels at 50 mph. The truck can travel 20 miles on a gallon of gas if it is travelling at 50mph. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 mph?
A/ 160 min B/ 180 min C/ 190 min D/ 192 min E/ 195 min
Originally posted by gmat1220 on 27 Feb 2011, 12:04.
Last edited by gmat1220 on 27 Feb 2011, 12:11, edited 1 time in total.



Manager
Joined: 26 Feb 2012
Posts: 88
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
20 Aug 2013, 06:17
Hi Bunuel
Can u clarify, is gallon consumption has to play a vital part to solve it??? I don't think so. Its mentioned to make someone confused...
Rgds Prasannajeet



Manager
Joined: 26 Feb 2012
Posts: 88
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
20 Aug 2013, 07:15
Hi Bunuel
Understood and thanx for explanation
Rgds Prasannajeet



Math Expert
Joined: 02 Sep 2009
Posts: 59268

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
20 Aug 2013, 07:48
VeritasPrepRon wrote: faifai0714 wrote: When a truck travels at 60 miles per hour, it uses 30% more gasoline to travel any distance than it does when it travels at 50 miles per hour. The truck can travel 20 miles on a gallon of gas if it is traveling at 50 miles per hour. The truck has only 10 gallons of gas and is 160 miles from its destination. It takes 20 minutes for the truck to stop for gas. How long will it take the truck to reach its final destination if the truck is driven at 60 miles per hour?
A. 160 minutes B. 180 minutes C. 190 minutes D. 192 minutes E. 195 minutes The answer is indeed B, but I feel like this question could be made more interesting (or perhaps just harder) if we introduced a choice. The driver can drive at 50 mph or 60 mph. What is the minimum amount of time he could take to reach his destination. Then we'd need to add in 160 miles / 50 mph = 3.2 hours, or 180 minutes + (\(\frac{1}{5} * 60\)) = 192 minutes (not coincidentally answer choice D). Then we could compare D to B and determine that going 60 mph is faster than 50 and pick B as the overall answer. Of course this might make people think that if he drove at ~55 mph he'd probably get there in under 3 hours without having to refuel. Just fuel for understanding GMAT algebra concepts! Thanks! Ron +1. Thank you Ron for giving me an idea for a question.
_________________



Intern
Status: Student
Joined: 13 Apr 2015
Posts: 5
Location: Bangladesh
Concentration: Human Resources, Economics
GPA: 3.5

Re: When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
26 Jun 2018, 06:04
asaf wrote: @60 mph mileage = (1  0.3) * 20 = 14 mpg
Time = Distance/speed TIme = 160/60 hours Time = 160/60 * 60 minutes Time = 160 minutes. Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,
Time = 160 + 20 = 180.
ANSWER: B The consumption of fuel depends on time or distance, on which one? Please make me clear.



Intern
Joined: 29 Aug 2017
Posts: 27
Location: India
Concentration: General Management, Leadership
GPA: 4

When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
26 Jun 2018, 09:31
Naren7 wrote: asaf wrote: @60 mph mileage = (1  0.3) * 20 = 14 mpg
Time = Distance/speed TIme = 160/60 hours Time = 160/60 * 60 minutes Time = 160 minutes. Since the truck is using gas at the rate of 14 mpg and there are only 10 gallons. So,
Time = 160 + 20 = 180.
ANSWER: B The consumption of fuel depends on time or distance, on which one? Please make me clear. Yes exactly. I also thought different from everyone. If travelling at 50 miles/hr  20 miles/gallon If travelling at 60 miles/hr (30% more fuel consumption that means 50miles/hr will have 30% more distance) = 20x(10/13). So it should be made clear in the question. And then solution becomes critical and answer comes 204 minutes.



Senior Manager
Status: Gathering chakra
Joined: 05 Feb 2018
Posts: 440

When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
Show Tags
04 Mar 2019, 06:20
Given: 50 mi/hr, gas = 20 mi/hr, 10 gal of gas
1) At 60 mi/hr gas consumption increases by 30% > (7/10)*20 mi/gal = 14 mi/gal
2) d = 160 mi, so in 10 gals we get 140 mi (this part takes 7/3 hrs) > 20 mi left
3) then refuel for 20 min, +1/3 hr
4) We still have to cover 20 miles, so 20mi/60 mi/hr = +1/3 hr
5) 7/3 + 1/3 + 1/3 = 9/3 = 3 hours*60 min/1 hr = 180 minutes
Is this a realistic 700 level rates question? The problem is not hard to do but the amount of information makes it time consuming.




When a truck travels at 60 miles per hour, it uses 30% more
[#permalink]
04 Mar 2019, 06:20






