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When an ice cream cone is sold at a 50 percent discount, it costs a do

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Bunuel
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When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   31 Dec 2021, 02:30
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When an ice cream cone is sold at a 50 percent discount, it costs a dollars and b cents. How many dollars do c ice cream cones cost at the regular price?


(A) \(c(\frac{100a+b}{100})\)

(B) \(20c(10a+b)\)

(C) \(c(\frac{200a+b}{100})\)

(D) \(c(\frac{100a+b}{50})\)

(E) \(2C(100a+b)\)



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Showmeyaa
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Re: When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   31 Dec 2021, 03:05
Bunuel wrote:
When an ice cream cone is sold at a 50 percent discount, it costs a dollars and b cents. How many dollars do c ice cream cones cost at the regular price?


(A) \(c(\frac{100a+b}{100})\)

(B) \(20c(10a+b)\)

(C) \(c(\frac{200a+b}{100})\)

(D) \(c(\frac{100a+b}{50})\)

(E) \(2C(100a+b)\)


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Let the regular price be represented by RP
a dollars and b cents = 100a + b cents
Also,

\(\frac{1}{2}\)RP = 100a + b
RP = 2(100a + b)
RP of 1 ice cream = 2(100a + b)
RP of c ice creams = 2c(100a + b)

IMO, (E)!
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When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   Updated on: 31 Dec 2021, 08:29
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Bunuel wrote:
When an ice cream cone is sold at a 50 percent discount, it costs a dollars and b cents. How many dollars do c ice cream cones cost at the regular price?


(A) \(c(\frac{100a+b}{100})\)

(B) \(20c(10a+b)\)

(C) \(c(\frac{200a+b}{100})\)

(D) \(c(\frac{100a+b}{50})\)

(E) \(2C(100a+b)\)



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Converting dollar to cents, a dollars will become 100a cents.
So total amount = 100a + b
Let the original cost price be x.
50% discount makes the value as x/2

So x/2 = 100a+b
x = 200a +2b

So cost of c ice-creams at this rate = c(200a +2b) or 2c(100a+b)
Converting into dollars c(100a+b/50)Option D

Originally posted by ElninoEffect on 31 Dec 2021, 03:26.
Last edited by ElninoEffect on 31 Dec 2021, 08:29, edited 1 time in total.
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Re: When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   31 Dec 2021, 08:30
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kapil1995 wrote:
ElninoEffect wrote:
Bunuel wrote:
When an ice cream cone is sold at a 50 percent discount, it costs a dollars and b cents. How many dollars do c ice cream cones cost at the regular price?


(A) \(c(\frac{100a+b}{100})\)

(B) \(20c(10a+b)\)

(C) \(c(\frac{200a+b}{100})\)

(D) \(c(\frac{100a+b}{50})\)

(E) \(2C(100a+b)\)



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Converting dollar to cents, a dollars will become 100a cents.
So total amount = 100a + b
Let the original cost price be x.
50% discount makes the value as x/2

So x/2 = 100a+b
x = 200a +2b

So cost of c ice-creams at this rate = c(200a +2b) or 2c(100a+b) Option E



Question asks Answer in dollars , Your answer is in cents

Convert it to dollars , will get \(c(\frac{100a+b}{50})\) Option D correct


Nice catch.! -given kudos.
Silly Mistakes and my life. :D
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Re: When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   31 Dec 2021, 12:15
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When an ice cream cone is sold at a 50 percent discount, it costs a dollars and b cents. How many dollars do c ice cream cones cost at the regular price?


(A) \(c(\frac{100a+b}{100})\)

(B) \(20c(10a+b)\)

(C) \(c(\frac{200a+b}{100})\)

(D) \(c(\frac{100a+b}{50})\)

(E) \(2C(100a+b)\)

Solution:

50% of cost of ice cream = a + b/100 $

100% cost of ice cream in dollars = 2( 100a + b)/ 100 = (100a + b)/50

Cost of c ice creams = c(100a + b)/ 50

IMO D is correct
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Re: When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink] New post   26 Dec 2023, 20:29
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Re: When an ice cream cone is sold at a 50 percent discount, it costs a do [#permalink]
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