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When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?

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When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?  [#permalink]

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New post Updated on: 23 Jan 2016, 13:11
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Question Stats:

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When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(2^10)=?


A. 9^(2^9 )
B. 9^(2^10 )
C. 9^(3^9 )
D. 910
E. 99



*A solution will be posted in two days.

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Originally posted by MathRevolution on 11 Jan 2016, 15:56.
Last edited by ENGRTOMBA2018 on 23 Jan 2016, 13:11, edited 2 times in total.
Reformatted the question.
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Re: When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?  [#permalink]

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New post 11 Jan 2016, 20:08
MathRevolution wrote:
When k=odd, f(k)=2k and when k=even, f(k)=3k, f(210)=?


A. 9^(2^9 )
B. 9^(2^10 )
C. 9^(3^9 )
D. 910
E. 99



*A solution will be posted in two days.


Hi,

looking at the Q and the answer choices, I feel some signs are missing.
The Q should be something like this..

Quote:
Q. When k is odd, f(k)=2^k and when k is even, f(k)=3^k, f(2^10)=?

A. 9^(2^9 )
B. 9^(2^10 )
C. 9^(3^9 )
D. 9^10
E. 9^9

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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


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Re: When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?  [#permalink]

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New post 11 Jan 2016, 20:16
Quote:
Q. When k is odd, f(k)=2^k and when k is even, f(k)=3^k, f(2^10)=?

A. 9^(2^9 )
B. 9^(2^10 )
C. 9^(3^9 )
D. 9^10
E. 9^9


here k is 2^10 and so even..
so f(2^10)= 3^( 2^10)..
now to get this to base 9, we will square 3 and half the power..

\(3^{ 2^{10}}={3^2}^{\frac{{2^{10}}}{2}}\)..
= \(9^{2^9}\)..
ans A
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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


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Math Revolution GMAT Instructor
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Re: When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?  [#permalink]

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New post 13 Jan 2016, 18:08
When k=odd, f(k)=2k and when k=even, f(k)=3k, f(210)=?


A. 9^(2^9 ) B. 9^(2^10 ) C. 9^(3^9 ) D. 9^10 E. 9^9


-> f(210)=3^(2^10 )=3^((2)(2^9))=(〖3^2)〗^(2^9 )=9^(2^9 ). Therefore, the answer is A.
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Re: When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=?  [#permalink]

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New post 23 Jan 2016, 13:05
1
Moderators! Please re-write k as power of 2 & 3 f(k)=2k ... f(k)=3k in question as chetan2u suggested.
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Re: When k=odd, f(k)=2^k and when k=even, f(k)=3^k, f(210)=? &nbs [#permalink] 23 Jan 2016, 13:05
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